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ankoles [38]
3 years ago
13

which statement is true about the atomic mass? a. it is never greater than the atomic number b. it always equal the atomic numbe

r c. it always lowers the atomic number d. it can be greater than the atomic number
Physics
2 answers:
Karolina [17]3 years ago
6 0

Answer:

d. it can be greater than the atomic number          

Explanation:

Atomic mass number can be defined as the sum of number of protons and number of neutrons present in the nucleus of an atom. On the other hand, atomic number is determined by the number of protons present in the nucleus of the atom. Thus, atomic mass number can be equal or greater than the atomic number but cannot be less than it. Hydrogen has 1 proton and 0 neutrons. So, atomic mass number and atomic number are equal. For rest, the atomic mass number is greater than the atomic number. Thus, option d is correct.

Shtirlitz [24]3 years ago
5 0
D. it can be greater than the atomic number
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A car slows down at -5.00 m/s² until it comes to a stop after travelling 15.0 m. What was the initial speed of the car?
lapo4ka [179]
<h2>Answer: 12.24m/s</h2>

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Now, among the equations related to this type of motion we have the following that relates the velocity with the acceleration and the distance traveled:

V_{f}^{2}-V_{o}^{2}=2.a.d   (1)

Where:

V_{f} is the Final Velocity of the car. We are told "the car comes to a stop after travelling", this means it is 0.

V_{o} is the Initial Velocity, the value we want to find

a is the constant acceleration of the car (the negative sign means the car is decelerating)

d is the distance traveled by the car

Now, let's substitute the known values in equation (1) and find V_{o}:

0-V_{o}^{2}=2(-5m/{s}^{2})(15m)    (2)

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Multiplying by -1 on both sides of the equation:

V_{o}^{2}=150{m}^{2}/{s}^{2}    (4)

V_{o}=\sqrt{150{m}^{2}/{s}^{2}}    (5)

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5 0
3 years ago
a train leaves a station heading east at 50 mph from that same station a car drives north at a speed of 30mph after 3 hours how
Alecsey [184]

Answer:

d = 175 miles

Explanation:

Train is moving towards East with constant speed of 50 mph

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at the same time the distance moved by the car is given as

d_2 = 30(3) = 90 miles

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So the distance between them after t = 3 hours is given as

d= \sqrt{d_1^2 + d_2^2}

d = \sqrt{150^2 + 90^2}

d = 175 miles

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