The angle turned through the flywheel of a generator during a time interval t is given by theta = at + bt^3 -ct^4, where a, b, a
1 answer:
Answer:
α =
Explanation:
The angle, θ, has been given as:
θ =
To obtain angular acceleration, α, we have to differentiate the angle twice, with respect to time, t.
Differentiating once will yield the angular velocity, ω:
ω = dθ/dt =
This can then be differentiated to obtain angular acceleration:
α = dω/dt =
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Explanation:
It is given that,
Mass of the object, m = 0.8 g = 0.0008 kg
Electric field, E = 534 N/C
Distance, s = 12 m
Time, t = 1.2 s
We need to find the acceleration of the object. It can be solved as :
m a = q E.......(1)
m = mass of electron
a = acceleration
q = charge on electron
"a" can be calculated using second equation of motion as :
a = 16.67 m/s²
Now put the value of a in equation (1) as :
q = 0.0000249 C
or
Hence, this is the required solution.
Answer:
the period of the 16 m pendulum is twice the period of the 4 m pendulum
Explanation:
Recall that the period (T) of a pendulum of length (L) is defined as:
where "g" is the local acceleration of gravity.
SInce both pendulums are at the same place, "g" is the same for both, and when we compare the two periods, we get:
therefore the period of the 16 m pendulum is twice the period of the 4 m pendulum.