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3 years ago

What does the term organic mean in chemistry? natural containing carbon using no pesticides within the periodic table

Chemistry

2 answers:

Vera_Pavlovna [14]3 years ago

7 0

Answer: In chemistry, the term organic mean containing carbon.

Explanation:

Organic compounds are defined as the compounds which contain carbon, hydrogen and oxygen. Carbon is the main element present in organic compounds.

For example, human body is made up of carbon.

So basically, living species are made up of organic compounds.

On the other hand, species which do not contain carbon atoms and are non-living in nature are known as inorganic compounds.

For example, diamond, sulfur, water, nitrogen dioxide etc are inorganic substances.

Thus, we can conclude that in chemistry, the term organic mean containing carbon.

dem82 [27]3 years ago

3 0

The organic meaning in chemistry is natural containing carbon.

<u><em> Explanation</em></u>

The natural matter or compounds which contain carbon are referred to as organic compounds.

Example of organic compound is protein which are made up of amino acid.

Amino acid is made up of carbon, hydrogen oxygen and nitrogen atoms.

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Explain why the atomic number is called the fingerprint of element

Dovator [93]

Answer:

No element shares the same atomic number. The atomic number of every element is unique to itself, just like a fingerprint is unique to a human. The atomic number of element allows us to identify it, like how we can identify a person from their fingerprint.

Explanation:

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2 years ago

What characteristic of rivers at their source gives them so much power to shape the land

Zielflug [23.3K]

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3 years ago

In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe

const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = $10^{-9} m$ .

Hence, 0.283 nm = $0.283 \times 10^{-9} m$

Formula for coulombic energy is as follows.

$U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}$

where, e = $1.6 \times 10^{-19}$ C

$\epsilon_{o}$ = $8.85 \times 10^{-12}$

$U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}$

= $1.423 \times 10^{-18} J$

As 1 eV = $1.6 \times 10^{-19} J$

So, 1 J = $\frac{1 eV}{1.6 \times 10^{-19}}$

Hence, U = $\frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}$

= 8.9 eV

Also, 1 J = $\frac{10^{-3} kJ}{6.022 \times 10^{23}mol}$

= $1.67 \times 10^{-27}$ kJ/mol

Therefore, U = $1.423 \times 10^{-18} J \times 1.67 \times 10^{-27}$ kJ/mol

= $2.37 \times 10^{-45} kJ/mol$

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3 years ago

What word or two-word phrase best describes the shape of the nitrite ( NO2- ) ion?

Olin [163]

I think the answer would be nitrogen

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3 years ago

Read 2 more answers

What is the average of atomic mass of carbon if 98.90% of the atoms are c-12 and 1.100% are c-13 atoms?

Paladinen [302]

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2 years ago