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3 years ago

Which of the following statement describes an actual orbit

2 answers:

7 0

I suppose right answer is d because staellite means an object that move around the larger object and Jupiter also moves around the Sun

Papessa [141]3 years ago

6 0

Answer:

The Moon is a satellite of Earth

Explanation:

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A race car travels 40 m/s around a banked (45° with the horizontal) circular (radius = 0.20 km) track. What is the magnitude of

OLEGan [10]

Answer:

c) $F_{net} = 0.640 kN$

Explanation:

As we know that resultant force is the net force that is acting on the system

As per Newton's II law we know that net force is product of mass and acceleration

so we will have

$F_{net} = ma$

here we know

m = 80 kg

for circular motion acceleration is given as

$a_c = \frac{v^2}{R}$

$a_c = \frac{40^2}{200} = 8 m/s^2$

now we have

$F_{net} = 80 \times 8$

$F_{net} = 640 N$

$F_{net} = 0.640 kN$

7 0

2 years ago

A small metal object is tied to the end of a string and whirled round a circular path of radius 30cm. The object makes 20 oscill

LUCKY_DIMON [66]

Answer:

(i) The angular speed of the small metal object is 25.133 rad/s

(ii) The linear speed of the small metal object is 7.54 m/s.

Explanation:

Given;

radius of the circular path, r = 30 cm = 0.3 m

number of revolutions, n = 20

time of motion, t = 5 s

(i) The angular speed of the small metal object is calculated as;

$\omega = \frac{20 \ rev}{5 \ s} \times \frac{2 \pi \ rad}{1 \ rev} = \frac{40\pi \ rad}{5 \ s} = 8\pi \ rad/s = 25.133 \ rad/s$

(ii) The linear speed of the small metal object is calculated as;

$v = \omega r\\\\v = 25.133 \ rad/s \ \times \ 0.3 \ m\\\\v = 7.54 \ m/s$

6 0

2 years ago

What is the internal resistor of the cell in closed circuit?

Drupady [299]

Generally, the internal resistance of the new battery is small, about 0.2 euros, while the old battery is large, close to 1 euro ，

5 0

2 years ago

MULTIPLE CHOICE

Juli2301 [7.4K]

Answer:

answers d

Explanation:

hopes its healp

8 0

1 year ago

Read 2 more answers

DETERMINE THE BCD EQUIVALENT OF 1100111110101001

Solnce55 [7]

Answer: It states that the BCD equivalent would be 0001000100000000000100010001000100010000000100000001000000000001.

6 0

2 years ago