Answer: The energy incident on the solar panel during that day is
.
Explanation:
Given: Mass = 250 kg
Initial temperature = ![16^{o}C](https://tex.z-dn.net/?f=16%5E%7Bo%7DC)
Final temperature = ![38^{o}C](https://tex.z-dn.net/?f=38%5E%7Bo%7DC)
Specific heat capacity = 4200 ![J/kg^{o}C](https://tex.z-dn.net/?f=J%2Fkg%5E%7Bo%7DC)
Formula used to calculate the energy is as follows.
![q = m \times C \times (T_{2} - T_{1})](https://tex.z-dn.net/?f=q%20%3D%20m%20%5Ctimes%20C%20%5Ctimes%20%28T_%7B2%7D%20-%20T_%7B1%7D%29)
where,
q = heat energy
m = mass of substance
C = specific heat capacity
= initial temperature
= final temperature
Substitute the values into above formula as follows.
![q = 250 kg \times 4200 J/kg^{o}C \times (38 - 16)^{o}C\\= 250 kg \times 4200 J/kg^{o}C \times 22^{o}C](https://tex.z-dn.net/?f=q%20%3D%20250%20kg%20%5Ctimes%204200%20J%2Fkg%5E%7Bo%7DC%20%5Ctimes%20%2838%20-%2016%29%5E%7Bo%7DC%5C%5C%3D%20250%20kg%20%5Ctimes%204200%20J%2Fkg%5E%7Bo%7DC%20%5Ctimes%2022%5E%7Bo%7DC)
As it is given that water absorbs 25% of the energy incident on the solar panel. Hence, energy incident on the solar panel can be calculated as follows.
![\frac{25}{100} \times q = 250 kg \times 4200 J/kg^{o}C \times 22^{o}C\\q = 9.24 \times 10^{7} J](https://tex.z-dn.net/?f=%5Cfrac%7B25%7D%7B100%7D%20%5Ctimes%20q%20%3D%20250%20kg%20%5Ctimes%204200%20J%2Fkg%5E%7Bo%7DC%20%5Ctimes%2022%5E%7Bo%7DC%5C%5Cq%20%3D%209.24%20%5Ctimes%2010%5E%7B7%7D%20J)
Thus, we can conclude that the energy incident on the solar panel during that day is
.
In order to determine the angle of the refracted ray, we may apply Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is constant for a given wave when it passes through two different media. Mathematically, this is:
n₁sin(∅₁) = n₂sin(∅₂)
Where n is the refractive index. Substituting the values given into the equation:
1.0003 * sin(20°) = 1.33 * sin(∅)
∅ = 14.91
The angle of the refracted ray is 15°.
Answer:
240 ohms
Explanation:
From Ohms law we deduce that V=IR and making R the subject of the formula then R=V/I where R is resistance, I is current and V is coltage across. Substituting 120 V for V and 0.5 A for A then
R=120/0.5=240 Ohms
Alternatively, resistance is equal to voltage squared divided by watts hence ![\frac {120^{2}}{60}=240](https://tex.z-dn.net/?f=%5Cfrac%20%7B120%5E%7B2%7D%7D%7B60%7D%3D240)
Answer:
Given that
Dry-bulb temperature(T) =24°C
Wet-bulb temperature(Tw) = 17°C
Pressure ,P = 1 atm
As we know that psychrometric chart are drawn at constant pressure.
From the diagram
ω= specific humidity
Lets take these two lines Dry-bulb temperature(T) line and Wet-bulb temperature(Tw) cut at point P
From chart at point P
a)
Specific humidity,ω = 0.00922 kg/kg
b)
The enthalpy ( h)
h=47.59 KJ/kg
c)
The relative humidity, RH
RH= 49.58 %
d)
Specific volume ,
v= 0.853 m³/kg
Answer:
2,54 cm are equal to 1 inch
Explanation:
Doing the conversion:
![55[cm]*\frac{1[inch]}{2,54[cm]} =21,65[inch]](https://tex.z-dn.net/?f=55%5Bcm%5D%2A%5Cfrac%7B1%5Binch%5D%7D%7B2%2C54%5Bcm%5D%7D%20%3D21%2C65%5Binch%5D)