(H+)(OH-) = Kw
kw= 1 x10^-14
OH-= 1 x10 ^-11
(H+)= KW / OH-
concentration of H+ = (1x10^-14) /.(1 x 10 ^-11) = 1 x10 ^-3
Ph= -log (H+)
PH=-log ( 1 x 10 ^-3) = 3 therefore the solution is acidic since the PH less than 7
A. India-southeastern Asia monsoons
This is the electron configuration of neptunium:
<span>Rn 5f4 6d1 7s2
</span>or, if you want to complicate:
<span>1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p6 7s2 5f4 6d1
</span>Since there are 93 electrons, they make up 5f4 altogether.