Answer:
2.765amu is the contribution of the X-19 isotope to the weighted average
Explanation:
The average molar mass is defined as the sum of the molar mass of each isotope times its abundance. For the unknown element X that has 2 isotopes the weighted average is defined as:
X = Mass X-19 * Abundance X-19 + MassX-21 * Abundance X-21
The contribution of the X-19 isotope is its mass (19.00 amu) times its abundance (14.55% = 0.1455). That is:
19.00amu * 0.1455 =
2.765amu is the contribution of the X-19 isotope to the weighted average
Answer:
answer is option 2 hope it helps
Answer:
125.5 ×10^-3 m^3= 0.1255 m^3
Explanation:
Volume=5.6mol×22.414dm^3
=125.5dm^3
Answer:
C. because the 4s orbital is at a lower energy level
So that they will mix in better, or more easily. However you want to say it.