An observer sees a flower pot sail up and then back down past a window 2.45 m high. If the total time the pot is in the sight is
1 answer:
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Answer: An archer pulls her bowstring back 0.400m by exerting a force that increases uniformly from zero to 230N. The equivalent spring constant of the bow will be 575N/m
Explanation: To find the answer, we have to know about the Simple Harmonic Motion.
<h3>What is Simple Harmonic Motion?</h3>- A particle is said to execute simple harmonic motion, if it moves to and fro about mean position under the action of restoring force.
- The restoring force is directly proportional to its displacement from the mean position and always directed towards the mean position.
- If x is the displacement from the mean position, and F is the restoring force, then
∝
where, k is called the spring constant.
- Given that, an archer pulls her bowstring back 0.400m by exerting a force that increasing from zero to 230N.
- Here, from the question given, we can write,
and
.
- Thus, our spring constant k will be,
Thus, we can conclude that, the equivalent spring constant of the bow will be 575N/m.
Learn more about the Simple Harmonic Motion here:
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<h3 />Explanation:
It is given that, the volume of air is 53.28 m³. We need to convert it into scientific notation.
Any number in scientific notation can be given by :
a is real no and b is any integer
We have, V = 53.28 m³
To write it into scientific notation, shift decimal before 3 such that,
No multiply and divide by 10. So,
So, the correct option is (a).