Answer:
31.905 ft/s²
Explanation:
Given that
Mass of the pilot, m = 120 lb
Weight of the pilot, w = 119 lbf
Acceleration due to gravity, g = 32.05 ft/s²
Local acceleration of gravity of found by using the relation
Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)
119 = 120 * a/32. 174
119 * 32.174 = 120a
a = 3828.706 / 120
a = 31.905 ft/s²
Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²
Distance = (speed) x (time)
Distance = (0.5 m/s) x (2.3 s)
Distance = (0.5 x 2.3) m
Distance = 1.15 meters
Analog
Television transmitters use one of two different technologies: analog, in which the picture and sound are transmitted by analog signals modulated onto the radio carrier wave, and digital in which the picture and sound are transmitted by digital signals.
Answer:Frequency = 3.525 Hertz
Explanation:In static equilibrium, kd =mg
Where k= effective spring constant of the spring.
mg= The weight of the car.
d= static deflection.
Therefore, w =SQRTg/d
w = SQRT 9.81/0.02
w= 22.15 rad/sec
Converting to Hertz unit for frequency
1 rad/s = 0.1591
22.15rad/s=?
22.15 × 0.1591= 3.525 hertz
The mass is the number of n + p if you subtract p from mass you will find n
164 - 59 = 105
