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8_murik_8 [283]
3 years ago
15

Barometer is taken from the base to the top of a 279-m tower. assuming the density of air is 1.29 kg/m3, what is the measured ch

ange in pressure?
Physics
1 answer:
torisob [31]3 years ago
8 0
<span>Answer : P = 3527 Pa Explanation: Given : height, h = 279 m and density of air , Ď = 1.29 kg/m3 Change in pressure , P = h*Ď*g We know that gravity, g = 9.8 m/s2 Therefore P = 279 * 1.29 * 9.8 = 3527 Pa</span>
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What does the model below represent?
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Answer:

D

Explanation:

Because we have two reactants and product

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2 years ago
Two forces (4N and 3N) pull your the left, while a 12N force pulls to the right. What is the net force
Lapatulllka [165]

Answer:

The answer is 11N to the right

Explanation:

Because 4N-3N= 1N

Therefore, 12N-1N=11N

The netforce is 11N to the right, because the greatest force is 12N to the right so it is more likely that the object is being pulled to the right.

8 0
3 years ago
Which of these was Sir Isaac Newton not known for? invention of calculus invention of the microscope the Three Laws of Motion un
Akimi4 [234]
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3 0
4 years ago
Read 2 more answers
Three charges are enclosed inside a spherical closed surface. The net flux through the surface is −216 N · m2/C. If two of the c
sladkih [1.3K]

Answer:

q₃ = -4.81 nC

Explanation:

We can use the Gauss Law here:

∅ = q/∈₀

where,

∅ = Net Flux = - 216 N.m²/C

q = total charge enclosed inside sphere = ?

∈₀ = permittivity of free space = 8.85 x 10⁻¹² C/N.m²

Therefore,

- 216 N.m²/C = q / 8.85 x 10⁻¹² C²/N.m²

q = (-216 N.m²/C)(8.85 x 10⁻¹² C²/N.m²)

q = - 1.91 nC

So, the total charge will be sum of all three charges:

q = q₁ + q₂ + q₃

- 1.91 nC = 1.74 nC + 1.16 nC + q₃

q₃ = - 1.91 nC - 1.74 nC - 1.16 nC

<u>q₃ = -4.81 nC</u>

5 0
3 years ago
How much power should a braked 1.5t car have to be braked to reduce its speed from 30m / s to 10m / s in 5s?​
grandymaker [24]

Answer:

-120000 W

Explanation:

Power = change in energy / time

P = ΔE / t

P = (½ mv₂² − ½ mv₁²) / t

P = m (v₂² − v₁²) / (2t)

Given m = 1.5 t = 1500 kg, v₂ = 10 m/s, v₁ = 30 m/s, and t = 5 s:

P = (1500 kg) ((10 m/s)² − (30 m/s)²) / (2 × 5 s)

P = -120000 W

7 0
3 years ago
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