Answer:
Nucleophilic reaction
and
Explanation:
A nucleophilic reaction is a type of reaction that involves attack of a specie having a negative charge or a lone pair of electrons on a positive center. This negatively charged specie or specie having a lone pair of electrons is called a nucleophile.
An SN2 reaction is a bimolecular, concerted nucleophilic reaction that leads to inversion of configuration at the carbon center. The leaving group is the group that departs from the frontside of the molecule as the nucleophile attacks from the backside.
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Answer:
1.Mg+O2.......MgO2
Explanation:
2.Very reactive towards halogens and reacts with water at room temperature. 3, Magnesium oxide is a simple basic oxide. 4.It will react with water to form magnesium hydroxide which is a base turning red litmus to blue 5.should be white. hope it helped. I help people although when I post a question it is left unanswered and then gets answers after two days when I don't really need it
Answer:
Peropanamide participates in hydrogen bonding because it has the highest boiling point.
N, N-dimethyl formamide has the lowest boiling point due to the lack of hydrogen bonding
Explanation:
Compare N-methylacetamide with its amide isomers propanamide and N,N- dimethylformamide. Which do you predict has the highest boiling point? The lowest?
Peropanamide participates in hydrogen bonding because it has the highest boiling point.
N, N-dimethyl formamide has the lowest boiling point due to the lack of hydrogen bonding
Solution:
We have to use the Henderson-Hasselbalch equation: for this calculation
Henderson–Hasselbalch equation describes the derivation of pH as a measure of acidity by using pKa, the negative log of the acid dissociation constant in biological and chemical systems. The equation is also useful for estimating the pH of a buffer solution and finding the equilibrium pH in acid-base reaction.
The equation is given by:
Here, [HA] is the molar concentration of the un dissociated weak acid, [A⁻] is the molar concentration (molarity, M) of this acid's conjugate base and pKa is −log10 Ka where Ka is the acid dissociation constant, that is:
pH = pKa + log([A^-]/[HA])
We look up the pKa for acetic acid:
pKa = 4.76
Let x = molarity of AcO^- and y = molarity of AcOH: Then we have the following two equations in two unknowns:
(1) x + y = 0.10 M
and
(2) 4.9 = 4.76 + log(x/y)
Further calcite the value of x and y by algebraic method and get the answer.