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Mashcka [7]
3 years ago
14

How do you calculate the rate of reaction?

Chemistry
1 answer:
SOVA2 [1]3 years ago
4 0

Answer:

You can calculate the rate of reaction by dividing the change in concentration by elapsed time.You can also find it graphically by finding the slope of the concentration curve.

Explanation:

rate=quantity/t(time)

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Which branch of the chemical industry usually requires advanced degrees? Marketing product development R & D corporate manag
fredd [130]

Answer: R & D is the correct option.

Explanation:

Research and development department of a chemical industry requires individuals holding advanced degrees because :

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4 0
3 years ago
For each trial, compute the mol of titrant; (molarity x L) and keep the number of significant figures to 4.
MrMuchimi

Answer:

Trial     Number of moles

           

  1          0.001249mol

  2         0.001232mol

  3          0.001187 mol

Explanation:

To calculate the <em>number of moles of tritant</em> you need its<em> molarity</em>.

Since the<em> molarity</em> is not reported, I will use 0.1000M (four significant figures), which is used in other similar problems.

<em>Molarity</em> is the concentration of the solution in number of moles of solute per liter of solution.

In this case the solute is <em>NaOH</em>.

The formula is:

          Molarity=\dfrac{\text{Number of moles of solute}}{\text{Volume of solution in liters}}

Solve for the <em>number of moles:</em>

          \text{Number of moles}=Molarity\times Volume\text{ }in\text{ }liters

Then, using the molarity of 0.1000M and the volumes for each trial you can calculate the number of moles of tritant.

Trial    mL           liters          Number of moles

           

1          12.49       0.01249        0.01249liters × 0.1000M = 0.001249mol

2         12.32      0.01232         0.01232liters × 0.1000M = 0.001232mol

3          11.87       0.01187         0.01187liters × 0.1000M = 0.001187 mol

3 0
3 years ago
Read 2 more answers
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8 0
3 years ago
Suppose that 6.2 mL of 2.1 M KOH(aq) is transferred to a 250 mL volumetric flask and diluted to the mark. It was found that 36.9
galina1969 [7]

Answer:

0.928 M

Explanation:

The concentration of acid can be determined by using the volume used and the concentration and volume used of base.

We will use the law of equivalence of moles.

M₁V₁=M₂V₂

M₁ = concentration of base used

V₁ = volume of base used

M₂ = concentration of acid used =? (to be determined)

V₂ = volume of acid used

The initial concentration of KOH used is diluted so let us find the final concentration of KOH after dilution

initial moles = final moles

initial concentration X initial volume = final concentration X final volume

6.2 X 2.1 = 250 X final concentration

final concentration = 0.052 M = M₁

V₁ = 36.9 mL

V₂ = 6.2 mL

Here with each mole of phosphoric acid three moles of KOH are used.

Therefore

3 M₁V₁ = M₂V₂

M₂ = \frac{V_{2}}{3M_{1}V_{1}}=0.928M

3 0
3 years ago
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