Answer:
F = 37.8 × 10^(6) N
Explanation:
The charges are 0.06 C and 0.07 C.
Thus;
Charge 1; q1 = 0.06 C
Charge 2; q2 = 0.07 C
Distance between them; r = 3 m
Formula for the force in between them is;
F = kq1•q2/r²
Where k is a constant = 9 × 10^(9) N.m²/C²
Thus;
F = (9 × 10^(9) × 0.06 × 0.07)/3²
F = 37.8 × 10^(6) N
Answer:
magnitude of net magnetic field at given point is
Explanation:
As we know that magnetic field due to a long current carrying wire is given as
here we we will find the magnetic field due to wire which is along x axis is given as
r = 2 m
now we have
into the plane
Now similarly magnetic field due to another wire which is perpendicular to xy plane is given as
r = 2 m
now we have
along + x direction
Since the two magnetic field is perpendicular to each other
So here net magnetic field is given as
Re do the experiment 3 times over again and if you get the same results then it should be correct
I would chose as the answer A I think that it uses so in the correctly.
Answer:
3000 N
Explanation:
<em>Newton's second law of motion</em> describes the relationship between an object's mass and the amount of force needed to accelerate it.
This law can be expresses as F=ma,
where
- F - force acting on an object
- m- the mass of an object
- a - its acceleration
The more mass an object has, the more force you need to accelerate it. And the greater the force, the greater the object's acceleration.
<em>F = ma</em>
<em>F = 1000×3 </em>
<em> = 3000 N</em>
