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Ann [662]
3 years ago
5

A sample of O2 occupies 75 L at 1 ATM. If the volume of the sample doubles, what is the new pressure of O2?

Physics
1 answer:
denis23 [38]3 years ago
3 0

Answer:0.50 atm

Explanation:(1atm)(75 L)=p2(150 L)

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An electron (charge = –1.6 x 10–19 C) is moving at 3.0 x 105 m/s in the positive x direction. A magnetic field of 0.80 T is in t
Marta_Voda [28]

Answer:

F = 3.84*10^-34N ^j

Explanation:

In order to calculate the magnetic force on the electron you use the following formula:

\vec{F}=q\vec{v} \ X\ \vec{B}       (1)

q: charge of the electron = -1.6*10^-19C

B: magnitude of the magnetic field = 0.80T

v: speed of the charge = 3.0*10^5 m/s

The direction of the motion of the electron is in the +i^ direction (+x direction). The magnetic field is in the +^k direction (+z direction).

The cross product between these unit vectors, by taking into account the minus sign of the charge, is given by:

-^i X ^k = ^j

The magnetic force is in the ^j direction (+y direction).

The magnitude of the magnetic force is:

F=qvB=(1.6*10^{-19}C)(3.0*10^5m/s)(0.80T)=3.84*10^{-34}N

The magnetic force on the electron has a magnitude of 3.84*10^-34N in the +y direction

7 0
3 years ago
If the temperature at the surface of Earth (at sea level) is 100°F, what is the temperature at 2000 feet if the average lapse ra
oksano4ka [1.4K]

Answer:

107 °F

Explanation:

Given that

The temperature at sea level = 100°F

height ,h= 2000 feet

The average lapse rate = 3.5°F/1000 feet

Given that rise in temperature 3.5°F per 1000 feet.

1000 feet ⇒ 3.5°F

Given that 2000 feet

2000 feet ⇒ 3.5°F x 2 +100°F

2000 feet ⇒ 107 °F

Therefore the temperature will be 107 °F  .

6 0
3 years ago
A current-carrying wire oriented north-south and laid over a compass deflects the compass 8° to the east. What is the magnitude
zhenek [66]

2.8 \times 10^{-6}\ T is the magnitude of the magnetic field made by the current

<u>Explanation:</u>

Given data:

\theta=8^{\circ}

Magnetic field of earth, B_{\text {earth}}=2 \times 10^{-5}\ \text {tesla}

We need to find the magnetic field of wire, B_{\text {wire }}

The compass needle moves toward a direction of magnetic field. The current in wire makes a magnetic field in available space where the compass is on the ground. The vector sum of the Earth's magnetic field and the wire's magnetic field represents the net magnetic field, as shown in the attached drawing, expressing the angle:

                   \tan \theta=\frac{B_{\text {wire}}}{B_{\text {earth}}}

By substituting the given values, we get

                  B_{\text {wire}}=\tan \theta \times B_{\text {earth}}=\tan 8^{\circ} \times 2 \times 10^{-5}=0.1405 \times 2 \times 10^{-5}

                  B_{\text {wire}}=0.28 \times 10^{-5}=2.8 \times 10^{-6}\ T

4 0
3 years ago
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