Question

To dilute a HCl solution from 0.400 M to 0.100 M the final volume must be

Answer 1

Answer:

The final volume must be 400 mL.

Explanation:

Let us assume the Initial volume as 100ml

Using dilution factor formula  

$\\ M_{1} \times V_{1}=M_{2} \times V_{2} \\\\ 0.400 M \times 100 m l=0.100 M \times V_{2}$

So,

$V_{2}=\frac{0.400 M \times 100 m l}{0.100 M}=400 m l$

Thus, the final volume must be 400 mL.

Answer 2

Explanation:

Molarity of HCl ,$M_1= 0.400 M$

Volume of the HCl solution = $V_1=500mL$ (assume)

Molarity of HCl after dilution $M_1= 0.100 M$

Volume of new HCl solution = $V_2$

$M_1V_1=M_2V_2$

$0.400 M\times 500 mL=0.100 M\times V_2$

$V_2=\frac{0.400 M\times 500 mL}{0.100 M}=2000 mL$

$\frac{V_1}{V_2}=\frac{500 mL}{2000 mL}$

$V_2=4\times V_1$

In order to dilute a HCl solution from 0.400 M to 0.100 M the final volume must be 4 times the initial volume of 0.400 M HCl solution .