PLEASE HELP Due today!

Monochromatic light of variable wavelength is incident normally on a thin sheet of plastic film in air. The reflected light is a

BartSMP [9]

Answer:

thickness t = 528.433 nm

Explanation:

given data

wavelength λ1 = 477.1 nm

wavelength λ2 = 668.0 nm

n = 1.58

solution

we know for constructive interference condition will be

2 × t × μ = (m1+0.5) × λ1 ....................1

2 × t × μ = (m2+0.5) × λ2 ....................2

so we can say from equation 1 and 2

(m1+0.5) × λ1 = (m2+0.5) × λ2

so

$\frac{\lambda 2}{\lambda 1} = \frac{m1+0.5}{m2+0.5}$ ..............3

put here value and we get

$\frac{668.0}{477.1} = \frac{m1+0.5}{m2+0.5}$

$\frac{m1+0.5}{m2+0.5}$ = 1.4

$\frac{m1+0.5}{m2+0.5} = \frac{7}{5}$ ...................4

so we here from equation 4

m1+0.5 = 7

m1 = 3 .................5

m2+0.5 = 4

m2 = 2 .................6

so now put value in equation 1

2 × t × μ = (m1+0.5) × λ1

2 × t × 1.58 = (3+0.5) × 477.1

solve it we get

thickness t = 528.433 nm

4 0

2 years ago

Part III: If a mouse and an elephant both run with the same kinetic energy, can you say which is running faster? Use the space b

Verdich [7]

Answer:

The mouse runs faster to have the same kinetic energy as the elephant.

Explanation:

Note from the equation given, mass (m) is directly proportional to KE. This means an elephant with more mass will have more KE, therefore, for the mouse to compensate, it has to run faster because its KE is smaller because of its small mass. If both run at the same speed, the elephant would have thousands of times more kinetic energy than the mouse. So the mouse has to run faster so that its speed compansates for its smaller weight.

3 0

3 years ago

Please help right now!!! MARK BRAINLIEST

hram777 [196]

For #2.
(A) The resultant velocity of the boat is the hypotenuse of a right triangle with the sides being the river and boat velocities.
The Pythagorean theorem: h^2 = a^2 + b^2
then you can use: soh cah toa to find any angles.
(B) The river velocity is not opposing the direction of travel, it increases the boats velocity from 2m/s to 2.5m/s

5 0

3 years ago

If vector A =i+2j-k and vec A cross vec B =3i-j+5k. find vec B

postnew [5]

Let B = a i + b j + c k. Then the cross product of A = i + 2j - k with B is

A × B = ( i + 2j - k ) × ( a i + b j + c k )

A × B = a ( i × i ) + 2a ( j × i ) - a ( k × i )

… … … + b ( i × j ) + 2b ( j × j ) - b ( k × j )

… … … + c ( i × k ) + 2c ( j × k ) - c ( k × k )

A × B = 0 - 2a k - a j

… … … + b k + 0 + b i

… … … - c j + 2c i - 0

A × B = (b + 2c) i + (-a - c) j + (b - 2a) k

So we have

3 i - j + 5 k = (b + 2c) i + (c - a) j + (b - 2a) k

which gives us the system of equations,

{ b + 2c = 3

{ -a - c = -1

{ -2a + b = 5

Solve for a, b, and c.

• Eliminate c from the first two equations:

(b + 2c) + 2 (-a - c) = 3 + 2 (-1)

-2a + b = 1

But -2a + b = 5, and 5 ≠ 1, so there is no such vector B that satisfies the cross product!

8 0

2 years ago

URGENT!!!!! If a 6 Ω resistor is in a circuit connected to a voltage source, and the current through the circuit is 2 amps, what

Eduardwww [97]

Answer:

Explanation:

according to ohms law we know that

v=IR

given current =2 amps

given resistance =6Ω

so voltage is

v=2*6 =12 V

3 0

3 years ago