G→Acceleration due to gravity=9.8m<span>s<span>−2</span></span>
So
<span>Acceleration of performer=1.5g=1.5×9.8m<span>s<span>−2</span></span>=14.7m<span>s<span>−<span>2</span></span></span></span>
Answer:
A, 24,000
Explanation: If I= Prt then
800 x 10 x 3 = 24,000.
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Equator------------------C::::::::::::::
Latitude------------------B::::::::::::::
Longitude---------------A::::::::::::::
D=Vot+1/2at^2
In this case, there is no initial y velocity so the term Vot=0 so d=1/2at^2
acceleration=acceleration due to gravity=-9.8m/s^2
It falls - 22cm or -0.22m
We have - 0.22=1/2(-9.8)t^2
t^2=(-0.44)/(-9.8)
t=sqrt[0.44/9.8]
A. False, because the SI unit for frequency is Hertz, 1 hertz equals 1 wave passing a fixed point in 1 second,
B. True, f and Nu (v)
C. To find the frequency of a wave, divide velocity of wave by wavelength
D. False, the period of a wave is measured in frequency (Hertz)