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mixas84 [53]
3 years ago
11

At what point is the KINETIC ENERGY at its highest?

Physics
1 answer:
igomit [66]3 years ago
8 0

Answer:

An object has the MOST kinetic energy when it's movement is the GREATEST.

Explanation:

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The normal force of a parked car is 15,000 Newtons. The coefficient of static friction between the rubber of the tires and the a
Shtirlitz [24]

Answer:

11250 N

Explanation:

From the question given above, the following data were obtained:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

Friction and normal force are related by the following equation:

F = μR

Where:

F is the frictional force.

μ is the coefficient of static friction.

R is the normal force.

With the above formula, we can calculate the frictional force acting on the car as follow:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

F = μR

F = 0.75 × 15000

F = 11250 N

Therefore, the frictional force acting on the car is 11250 N

3 0
3 years ago
The force per meter between the two wires of a jumper cable being used to start a stalled car is 0.244 N/m. (a) What is the curr
MakcuM [25]

Answer: current I is 144amp(A)

Explanation: The force per lenght F/L, current l, and separation distance r are related by the formula

F/L = permeability of space* I²/2*pi*r

Permeability of free space is 1.257*EXP {-6} Henry/meter

F/L is 0.244 N/m, pi is 3.142,

r is 1.7cm which is equal to 0.017meter.

I is what we are looking for.

Now we have after substitution,

0.244

= 1.257*EXP {-6} * I²/(2*3.142*0.017)

After cross multiplying and making I² subject of formula we have,

0.0261/(1.257*EXP {-6}) = I²

I = √{20736.7} =144ampere(A)

That means in each of the jumper wire there is 144amp(A)

8 0
3 years ago
(I) A car slows down from 28 m????s to rest in a distance of 88 m. What was its acceleration, assumed constant?
Nataly [62]

Answer:

The  value is  a = -  4.45 m/s^2

Explanation:

From the question we are told that  

       The  initial speed is  u  =  28 \  m/s at a distance of  s_1  =  0 \ m

        The  final speed is  v  =  0 \  m/s    at a distance of  s_2 =  88 \  m

Generally  from the  kinematic equation we have that

       v^2  =  u^2  +2as

=>   a = \frac{v^2  -  u^2  }{ 2(s_2  -  s_1 )}

=>  a = \frac{0 -  28^2  }{ 2(88  -  0 )}

=>   a = -  4.45 m/s^2

The negative sign shows that it is decelerating

6 0
4 years ago
A dog runs with an initial speed of 1.5 m/s on a floor. It slides to a stop with an acceleration of -0.35 m/s^2. How long does i
Neko [114]

Answer:

3.214 m

Explanation:

Here object is moving in a constant acceleration. Then we can use motion equations to find the total distance

V² = U² + 2as

0 = 1.5² + 2×-0.35 × s

s = 3.214 m

symbols has usual meanings.

6 0
3 years ago
Read 2 more answers
Help me with this problem please
zaharov [31]

Answer:

Total moment of inertia when arms are extended: 1.613 kg\,m^2

Explanation:

This second part of the problem could be a pretty complex one, but if they expect you to do a simple calculation, which is what I imagine, the idea is just adding another moment of inertia to the first one due to the arms extended laterally and use the moment of inertia for such as depicted in the image I am attaching.

In that image:

L is the length from one end to the other of the extended arms (each 0.75m from the center of the body) which gives 1.5 meters.

m is the mass of both arms. That is: twice 5% of the mass of the person: which mathematically can be written as: 2 * 0.05 * 56.5 = 5.65 kg

Therefore this moment of inertia to be added can be obtained using the formula shown in the image:

I_z=\frac{1}{12} \,m\,L^2\\\\I_z=\frac{5.65\,*\,1.5^2}{12} \\I_z=1.05937\,kg\,m^2

Now, one needs to add this to the previous moment that you calculated, resulting in:

0.554 + 1.059 = 1.613 kg\,m^2

5 0
3 years ago
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