All categories

3 years ago

A dog pushes against the front door for 3 seconds with a force of 88 N. What

Physics

1 answer:

kirill [66]3 years ago

5 0

264Ns

Explanation:

Given parameters:

Time of the push = 3s

Force of push = 88N

Unknown:

Impulse = ?

Solution:

Impulse is defined as the change in momentum of a body when force acts on it.

Impulse = Force x time

Inputting the parameters:

Impulse = 88 x 3 = 264Ns

Learn more:

Momentum brainly.com/question/9484203

#learnwithBrainly

You might be interested in

How much energy is required to ionize hydrogen when it is in the n = 5 state?

PtichkaEL [24]

Answer:

0.544 eV

Explanation:

To ionize the hydrogen atom $n_f\rightarrow infinte$

So the required energy is $\Delta E=13.6(\frac{1}{n_i^2}-\frac{1}{n_f^2})$ as $n_f\rightarrow infinte$

So $\Delta E=13.6\frac{1}{n_i^2}$

We have to calculate the energy required to ionize hydrogen atom when it is in n=5

So the energy should be less than $\Delta E=13.6\frac{1}{5^2}=0.544eV$

4 0

3 years ago

A car is traveling at 120 km/h (75 mph). When applied the braking system can stop the car with a deceleration rate of 9.0 m/s2.

Bumek [7]

Answer:

the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

Explanation:

Given that;

speed of car V = 120 km/h = 33.3333 m/s

Reaction time of an alert driver = 0.8 sec

Reaction time of an alert driver = 3 sec

extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec

now, extra distance that car will travel in case of sleepy driver will be'

S_d = V × 2.2 sec

S_d = 33.3333 m/s × 2.2 sec

S_d = 73.3333 m

hence, number of car of additional car length n will be;

n = S_n / car length

n = 73.3333 m / 5m

n = 14.666 ≈ 15

Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

8 0

4 years ago

You are sitting in a commercial jetliner. It is on the runway and ready to take off. Before it does, clever soul that you are, y

wariber [46]

Answer:

a.=4.78 m/s2

b. the thread will remain vertical

Explanation:

For jet acceleration as you know,

Weight due to gravity given as

F= w =mg

and body movement with acceleration as

F= ma

$tan\theta=\frac{ma}{mg}$

$tan\theta=\frac{a}{g}$

$a=gtan\theta$

$a=9.81\times tan 26^{0}$

$a=4.78\frac{m}{s^{2} }$

Its acceleration of plane

For planes attaining constant velocity

a = 0 and tan∅ = 0

so Ф = 0

hence the thread will be remain vertical

4 0

3 years ago

Please help im being timed on this and need to get my grade up

nadya68 [22]

Answer:

a I think hope this helps

8 0

3 years ago

A car is pushed and travels 12 m. The same car is then pushed and it travels 15m. What could of

Ipatiy [6.2K]

Explanation:

The force was increased

5 0

4 years ago