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Nat2105 [25]
4 years ago
6

ASAP! —Will Give Brainliest!Now that the lab is complete, it is time to write your lab report. The purpose of this guide is to h

elp you write a
clear and concise report that summarizes the lab you have just completed.
The lab report is composed of four sections:
Section 1: Experimental Overview

- Provide background information
- Include the hypothesis(es).

Summarize the procedures.
Section II: Data and Observations

- Summarize the data you collected in the lab guide.
Include information from data tables
- Include any written observations that are relevant.

Section III: Analysis and Discussion

- Discuss any important calculations or formulas used.
- identify key results, what the results indicate, and any trends in the data.
- Include graphs (if constructed) that display trends in the data.
- Provide possible reasons for any problems with the experiment, or unexpected data.

Section IV: Conclusions
o identify if the hypothesis(es) was (were) supported or refuted

- Provide logical reasoning based on data.
- Explain how the experiment could be improved.

Questions I have not answered yet. Please help me out:

-What do the key results indicate?

- If you constructed graphs, what trends do they indicate in your data?

-Were there any problems with the experiment or the methods? Did you have any surprising results?

- What do the results tell you about your hypothesis?

- How does the data support your claim above?
Chemistry
1 answer:
shtirl [24]4 years ago
3 0
Five points to do all the
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For the galvanic (voltaic) cell Fe(s) + Mn2+(aq) → Fe2+(aq) + Mn(s) (E°= 0.77 V at 25°C), what is [Fe2+] if [Mn2+] = 0.040 M and
avanturin [10]

Answer:

0.01836 M

Explanation:

Again the reaction equation is;

Fe(s) + Mn2+(aq) → Fe2+(aq) + Mn(s)

E°cell= 0.77 V

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[Mn2+] = 0.040 M

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n=2

From Nernst's equation;

Ecell= E°cell- 0.0592/n log Q

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0.78-0.77= - 0.0592/2 log [Fe2+] /[0.040]

0.01/ -0.0296= log [Fe2+] /[0.040]

-0.3378= log [Fe2+] /[0.040]

Antilog(-0.3378) = [Fe2+] /[0.040]

0.459= [Fe2+] /[0.040]

[Fe2+] = 0.459 × 0.040

[Fe2+] = 0.01836 M

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1. What is a forensic palyn ologist?
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Read 2 more answers
25) Base your answer on the information below and on your knowledge of chemistry. In a laboratory investigation, an HCl(aq) solu
Veseljchak [2.6K]

Answer:

Concentration of KOH is 0.02M

15.0 mL of a 1.0 M HCl(aq) solution is a better conductor of electricity because it is more concentrated and has greater ions in solution.

Explanation:

Equation of the reaction;

KOH(aq) + HCl(aq) ----> KCl(aq) + H2O(l)

To determine the concentration of the KOH

Concentration of acid CA= 0.010 M

Volume of acid VA= 15.0 ml

Concentration of base CB= ???

Volume of base VB= 7.5 ml

Number of moles of acid NA= 1

Number of moles of base NB= 1

From;

CAVA/CBVB= NA/NB

CAVANB = CBVBNA

CB= CAVANB/VBNA

Substituting values;

CB= 0.010 × 15.0 ×1 / 7.5 ×1

CB= 0.02 M

Therefore, the concentration of the KOH is 0.02M

15.0mL of 1.0 M HCl(aq) is a better conductor of electricity than 15.0mL of 0.010 M HCl(aq) because 15.0mL of 1.0 M HCl(aq) is more concentrated and has more ions in solution than 15.0mL of 0.010 M. Since ions are charge carriers in solution, the more the concentration of ions in solutions, the greater the conductivity of the solution. Hence the answer.

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3 years ago
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