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nikklg [1K]
3 years ago
14

Suppose a ball of putty moving horizontally with 1kg.m/s of momentum collides and sticks to an identical ball of puffy moving ve

rtically with 1 kg.m/s of momentum.What is the magnitude of their combined momentum? Why is their combined momentum not simply the arithmetic sum, 2 kg.m/s?
Physics
1 answer:
WARRIOR [948]3 years ago
5 0

Answer:

Vector sum of two vectors at right angles

p={p₁²+p₂²} =2 =1.41 kg•m/s

Explanation:

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You're driving down the highway late one night at 22 m/s when a deer steps onto the road 38 m in front of you. Your reaction tim
sleet_krkn [62]

speed of the car is given on the road

v = 22 m/s

reaction time is given as

t = 0.50 s

now we can find the distance that it will move during this reaction time

d_1 = 22* 0.50 = 11 m

now the deceleration of the car is 10 m/s^2

so the distance that it will move before stop is given by

v_f^2 - v_i^2 = 2 a d

0^2 - 22^2 = 2*(-10)*d

d = 24.2 m

so the total distance that it require to stop is given as

d = 24.2 + 11 = 35.2 m

while the deer is standing at distance 38 m

so the car will stop 2.8 m before the position of deer


3 0
3 years ago
Find the mass of a football player who's momentum is 630 kg•m/s backward and. is traveling at 7 m/s.
Setler [38]

Answer:

<h2>The answer is 90 kg</h2>

Explanation:

In order to find the mass of the football we use the formula

m =  \frac{p}{v}  \\

where

p is the momentum

v is the velocity

We have

m =  \frac{630}{7}  \\

We have the final answer as

<h3>90 kg</h3>

Hope this helps you

5 0
3 years ago
Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential difference of 170 V. An electron ent
notsponge [240]

Answer:

Explanation:

Electric field between plates

V / d

= 170 / ( 2 x 10⁻² )

= 8500 N/C

Force on electron in this field

= 8500 x 1.6 x 10⁻¹⁹

= 13600 x 10⁻¹⁹ N

Acceleration

= 13600 x 10⁻¹⁹ / 9.1 x 10⁻³¹

a = 1494.5 x 10¹² m /s²

s = .1 x 10⁻² m

v² = u² + 2as

=  (2.9x 10⁵)²+ 2 x 1494.5 x 10¹² x .1 x 10⁻²

= 8.41 x 10¹⁰ + 299 x 10¹⁰

= (8.41 + 299 ) x 10¹⁰

v = 17.53  x 10⁵ m /s

8 0
3 years ago
Investigators are researching the appearance of a strange movement of objects in what the local community considers a haunted ho
wolverine [178]

Answer:

0.18216 T

Explanation:

N = Number of turns = 219

A = Area = \pi r^2

r = Radius = 1 cm

\omega = Angular speed = 40\times 2\pi

Maximum emf is given by

\epsilon=NBA\omega\\\Rightarrow B=\dfrac{\epsilon}{NA\omega}\\\Rightarrow B=\dfrac{3.15}{219\times \pi 0.01^2\times 40\times 2\pi}\\\Rightarrow B=0.18216\ T

The strength of the magnetic field is 0.18216 T

8 0
3 years ago
Assume: The bullet penetrates into the block and stops due to its friction with the block. The compound system of the block plus
charle [14.2K]

Answer:

The total energy of the composite system is 7.8 J.

Explanation:

Given that,

Height = 0.15 m

Radius of circular arc = 0.27 m

Suppose, the entire track is friction less. a bullet with a m₁ = 30 g mass is fired horizontally into a block of wood with m₂ = 5.29 kg mass. the acceleration of gravity is 9.8 m/s.

Calculate the total energy of the composite system at any time after the collision.

We need to calculate the total energy of the composite system

Total energy of the system at any time = Potential energy of the system at the stopping point

E=mgh+Mgh

E=(m+M)gh

Put the value in to the formula

E=(30\times10^{-3}+5.29)\times 9.8\times0.15

E=7.8\ J

Hence, The total energy of the composite system is 7.8 J.

8 0
3 years ago
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