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nikklg [1K]
3 years ago
14

Suppose a ball of putty moving horizontally with 1kg.m/s of momentum collides and sticks to an identical ball of puffy moving ve

rtically with 1 kg.m/s of momentum.What is the magnitude of their combined momentum? Why is their combined momentum not simply the arithmetic sum, 2 kg.m/s?
Physics
1 answer:
WARRIOR [948]3 years ago
5 0

Answer:

Vector sum of two vectors at right angles

p={p₁²+p₂²} =2 =1.41 kg•m/s

Explanation:

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Two identical plastic cups contain the same amount of water at two different temperatures, as shown to the left. Both cups are p
Elza [17]

Answer:

the molecules will begin to move slowly and will turn to ice

Explanation:

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6 0
3 years ago
1. The Sun orbits the center of the Milky Way.<br> True False
Rudiy27

Answer:true

Explanation:

6 0
3 years ago
Read 2 more answers
You have a two-wheel trailer that you pull behind your ATV. Two children with a combined mass of 76.2 kg hop on board for a ride
marin [14]

a) The spring constant is 12,103 N/m

b) The mass of the trailer 2,678 kg

c) The frequency of oscillation is 0.478 Hz

d) The time taken for 10 oscillations is 20.9 s

Explanation:

a)

When the two children jumps on board of the trailer, the two springs compresses by a certain amount

\Delta x = 6.17 cm = 0.0617 m

Since the system is then in equilibrium, the restoring force of the two-spring system must be equal to the weight of the children, so we can write:

2mg = k'\Delta x (1)

where

m = 76.2 kg is the mass of each children

g=9.8 m/s^2 is the acceleration of gravity

k' is the equivalent spring constant of the 2-spring system

For two springs in parallel each with constant k,

k'=k+k=2k

Substituting into (1) and solving for k, we find:

2mg=2k\Delta x\\k=\frac{mg}{\Delta x}=\frac{(76.2)(9.8)}{0.0617}=12,103 N/m

b)

The period of the oscillating system is given by

T=2\pi \sqrt{\frac{m}{k'}}

where

And for the system in the problem, we know that

T = 2.09 s is the period of oscillation

m is the mass of the trailer

k'=2k=2(12,103)=24,206 N/m is the equivalent spring constant of the system

Solving the equation for m, we find the mass of the trailer:

m=(\frac{T}{2\pi})^2 k'=(\frac{2.09}{2\pi})^2 (24,206)=2,678 kg

c)

The frequency of oscillation of a spring-mass system is equal to the reciprocal of the period, therefore:

f=\frac{1}{T}

where

f is the frequency

T is the period

In  this problem, we have

T = 2.09 s is the period

Therefore, the frequency of oscillation is

f=\frac{1}{2.09}=0.478 Hz

d)

The period of the system is

T = 2.09 s

And this time is the time it takes for the trailer to complete one oscillation.

In this case, we want to find the time it takes for the trailer to complete 10 oscillations (bouncing up and down 10 times). Therefore, the time taken will be the period of oscillation multiplied by 10.

Therefore, the time needed for 10 oscillations is:

t=10T=10(2.09)=20.9 s

#LearnwithBrainly

7 0
3 years ago
3B with worked out equations please
bekas [8.4K]

Answer:

b) 1500N

c) to the right

Explanation:

Resultant force= 2000 -500= 1500N

Resultant force is a combination of 2 or more forces acting on an object.

4 0
3 years ago
You need to push a heavy box across a rough floor, and you want to minimize the average force applied to the box during the time
7nadin3 [17]

When pushing the body it is necessary to break the frictional force generated by the floor. Once this frictional force is overcome, the body will begin to move. Ideally, if a constant velocity is maintained or close to this value, the acceleration that will be exerted will tend to be zero and therefore, by Newton's second law the value of the Force will also tend to minimum values.

Remember that this law tells us that

F= ma

F= m \frac{\Delta v}{t}

Therefore the best strategy is A. keep pushing the box forward at a steady speed

7 0
3 years ago
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