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Charra [1.4K]
3 years ago
9

What scientific term is a well-tested explanation for a set of observations or experimental results?

Physics
1 answer:
lara31 [8.8K]3 years ago
6 0

b. theory............

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In classical physics, consider a 2 kg block hanging on a spring with a spring constant of 50 N/m. Ignore air resistance. The blo
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Answer:

v = 0

Explanation:

This problem can be solved by taking into account:

- The equation for the calculation of the period in a spring-masss system

T = \sqrt{\frac{m}{k} }     ( 1 )

- The equation for the velocity of a simple harmonic motion

x = \frac{2\pi }{T}Asin(\frac{2\pi }{T}t)   ( 2 )

where m is the mass of the block, k is the spring constant, A is the amplitude (in this case A = 14 cm) and v is the velocity of the block

Hence

T = \sqrt{\frac{2 kg}{50 N/m}} = 0.2 s

and by reeplacing it in ( 2 ):

v = \frac{2\pi }{0.2s}(14cm)sin(\frac{2\pi }{0.2s}(0.9s)) = 140\pi  sin(9\pi ) = 0

In this case for 0.9 s the velocity is zero, that is, the block is in a position with the max displacement from the equilibrium.

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3 years ago
Look at the resistor illustrated in the figure above. Based on your knowledge of the resistor color code, what are the resistanc
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A because of the resistors are four in this options first option is multiplied by 4
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What is the displacement for the couple's hiking trip? Give your answer as an ordered pair, with magnitude first, followed by a
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Explanation:

See the attached

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A pin fin of uniform, cross-sectional area is fabricated of an aluminum alloy (k = 160 W/m-K). The fin diameter is D = 4 mm, and
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Answer:

Given that

D= 4 mm

K = 160 W/m-K

h=h = 220 W/m²-K

ηf = 0.65

We know that

m=\sqrt{\dfrac{hP}{KA}}

For circular fin

m=\sqrt{\dfrac{4h}{KD}}

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m = 37.08

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0.65=\dfrac{tanh37.08L}{37.08L}

By solving above equation we get

L= 36.18 mm

The effectiveness for circular fin given as

\varepsilon =\dfrac{2\ tanhmL}{\sqrt{\dfrac{hD}{K}}}

\varepsilon =\dfrac{2\ tanh(37.08\times 0.03618)}{\sqrt{\dfrac{220\times 0.004}{160}}}

ε = 23.52

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3 years ago
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The loudness of sound is determined by what?
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The amplitude of a sound<span> wave </span>determines<span> its </span>loudness<span> or volume. A larger amplitude means a louder </span>sound<span>, and a smaller amplitude means a softer </span><span>sound</span>
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