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3 years ago

15

Which type of reaction does this diagram represent? A small ball heads toward a large circle labeled superscript 235 upper U. An

arrow points to an irregular circle labeled superscript 236 upper U. Another arrow points to a starburst, partially overlaid by 2 blobs labeled superscript 92 upper K r and superscript 141 upper B a, and with 3 small balls heading away from the starburst.

2 answers:

marysya [2.9K]3 years ago

7 0

Answer:

Nuclear fission of U235 to Kr92 and Ba 141.

Explanation:

Nuclear fission is the spantenous disintegration or breaking down of a big atom into smaller nucleus with the release of huge amount of energy. It involves the artificial transmutation of a heavier nucleus by bombardment with other rasuiactive particles.

Scorpion4ik [409]3 years ago

6 0

Answer:

nuclear fission because an atom is splitting into two large fragments of comparable mass

Explanation:

b

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A speck of dust with mass 12 mg and electric charge 10 μC is released from rest in a uniform electric field of magnitude 850 N/C

Marta_Voda [28]

Answer:

$a=708.3m/s^2$

Explanation:

The force experimented by a charge <em>q </em>in a uniform electric field <em>E</em><em> </em>is <em>F=qE</em>.

Newton's 2nd Law tells us that the relation between acceleration <em>a</em> a mass <em>m </em>experiments when a force <em>F </em>is applied to it is <em>F=ma</em>.

Combining these equations we have <em>am=qE</em>, and since we want the acceleration of the speck of dust, we substitute our values:

$a=\frac{qE}{m}=\frac{(10\times10^{-6}C)(850N/C)}{12\times10^{-6}Kg}=708.3m/s^2$

4 0

3 years ago

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Evgen [1.6K]

Answer:

53.33 seconds

Explanation:

From the question;

Power of the motor is 75 kW or 75000 W
Depth or height is 150 m
Volume of water is 400 m³

We are required to determine taken to raise the water from the given height.

We know that density of water is 1000 kg/m³

Therefore;

Mass of water = 400 m³ × 1000 kg/m³

= 4.0 × 10^5 kg

Thus, force required to raise the water;

= 4.0 × 10^5 kg × 10 N/kg

= 4.0 × 10^6 N

To determine the time;

we use the formula;

Time = work done ÷ power

= (4.0 × 10^6 N × 150 m) ÷ 75000 Joules/s

= 53.33 seconds

Therefore, time taken to raise the water is 53.33 seconds

8 0

3 years ago

Write the energy conversion when climbing a ladder

Volgvan

A child climbing a ladder is transforming kinetic energy into potential energy.

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3 years ago

A freshly prepared sample of radioactive isotope has an activity of 10 mCi. After 4 hours, its activity is 8 mCi. Find: (a) the

Maurinko [17]

Answer:

(a). The decay constant is $1.55\times10^{-5}\ s^{-1}$

The half life is 11.3 hr.

(b). The value of N₀ is $2.38\times10^{11}\ nuclei$

(c). The sample's activity is 1.87 mCi.

Explanation:

Given that,

Activity $R_{0}=10\ mCi$

Time $t_{1}=4\ hours$

Activity R= 8 mCi

(a). We need to calculate the decay constant

Using formula of activity

$R=R_{0}e^{-\lambda t}$

$\lambda=\dfrac{1}{t}ln(\dfrac{R_{0}}{R})$

Put the value into the formula

$\lambda=\dfrac{1}{4\times3600}ln(\dfrac{10}{8})$

$\lambda=0.0000154\ s^{-1}$

$\lambda=1.55\times10^{-5}\ s^{-1}$

We need to calculate the half life

Using formula of half life

$T_{\dfrac{1}{2}}=\dfrac{ln(2)}{\lambda}$

Put the value into the formula

$T_{\dfrac{1}{2}}=\dfrac{ln(2)}{1.55\times10^{-5}}$

$T_{\dfrac{1}{2}}=44.719\times10^{3}\ s$

$T_{\dfrac{1}{2}}=11.3\ hr$

(b). We need to calculate the value of N₀

Using formula of $N_{0}$

$N_{0}=\dfrac{3.70\times10^{6}}{\lambda}$

Put the value into the formula

$N_{0}=\dfrac{3.70\times10^{6}}{1.55\times10^{-5}}$

$N_{0}=2.38\times10^{11}\ nuclei$

(c). We need to calculate the sample's activity

Using formula of activity

$R=R_{0}e^{-\lambda\times t}$

Put the value intyo the formula

$R=10e^{-(1.55\times10^{-5}\times30\times3600)}$

$R=1.87\ mCi$

Hence, (a). The decay constant is $1.55\times10^{-5}\ s^{-1}$

The half life is 11.3 hr.

(b). The value of N₀ is $2.38\times10^{11}\ nuclei$

(c). The sample's activity is 1.87 mCi.

4 0

4 years ago

J-s. If your 1400-kg car is parked in an 8.54-m-long garage, what is the uncertainty in its velocity? cm/s the tolerance is +/-2

IgorC [24]

Answer:

$\Delta v = 4.41 \times 10^{-37} cm/s$

Explanation:

As per Heisenberg's uncertainty principle we know that

$\Delta P \times \Delta x = \frac{h}{4\pi}$

so here we have

$\Delta P = m\Delta v$

$\Delta x = 8.54 m$

now from above equation we have

$m\Delta v \times (8.54) = \frac{h}{4\pi}$

$1400(\Delta v) \times (8.54) = \frac{6.626 \times 10^{-34}}{4\pi}$

$\Delta v = 4.41 \times 10^{-39} m/s$

$\Delta v = 4.41 \times 10^{-37} cm/s$

8 0

3 years ago