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natali 33 [55]
3 years ago
8

For a weak acid such as the side chain ε-amino group of a lysine residue in a protein, if the pKa of that specific residue's ε-a

mino group is exactly 10.0, in an environment in which the pH = 9.0, what would be the ratio of base to acid?
Chemistry
1 answer:
Neko [114]3 years ago
6 0

Answer:

0.1

Explanation:

Using Henderson-Hasselbalch equation

pH = pKa + log ( base / acid )

pH= 9.0 , pKa = 10.0

9.0 = 10 + log ( base / acid )

9 - 10 = log ( base / acid )

10⁻¹ = ( base / acid )

( base / acid ) = 0.1

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bagirrra123 [75]

Answer:

At birth, there are approximately 1 million eggs; and by the time of puberty, only about 300,000 remain. Of these, only 300 to 400 will be ovulated during a woman's reproductive lifetime. Fertility can drop as a woman ages due to decreasing number and quality of the remaining eggs.

Explanation:

Hope This Helps!!

5 0
3 years ago
Read 2 more answers
A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
vichka [17]

Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

3 0
3 years ago
A brownish haze that is a mixture of ozone and other chemicals, formed when pollutants react with each other in the presence pf
soldi70 [24.7K]
The haze is called smog, hope this helps, pls mark brainliest!
8 0
4 years ago
If a substance has a mass of 12.50 g and takes up 3.4 mL of space, what is the density?
miskamm [114]

Answer:

The answer is

<h2>3.68 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>density =  \frac{mass}{volume}</h3>

From the question

mass of substance = 12.50 g

volume = 3.4 mL

The density of the substance is

density =  \frac{12.50}{3.4}  \\  = 3.676470588...

We have the final answer as

<h3>3.68 g/mL</h3>

Hope this helps you

7 0
3 years ago
Please help :) thanks
Gnesinka [82]

Explanation:

it is the one you have selected because it is the only solid one

7 0
3 years ago
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