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pychu [463]
3 years ago
10

You throw a snowball horizontally. It hits a target 2 meters away. You notice that it hit o.9m below where you aimed. With what

horizontal velocity did you throw the snowball?
Physics
1 answer:
ludmilkaskok [199]3 years ago
3 0

The snowball travels a horizontal distance <em>x</em> and has height <em>y</em> at time <em>t</em> according to

<em>x</em> = <em>vt</em>

<em>y</em> = 0.9 m - 1/2 <em>gt</em> ²

where <em>g</em> = 9.8 m/s² is the magnitude of the acceleration due to gravity.

Set <em>y</em> = 0 and solve for <em>t</em> :

0 = 0.9 m - 1/2 <em>gt</em> ²

<em>t</em> ² = (1.8 m) / <em>g</em>

<em>t</em> ≈ 0.43 s

The target is 2 m away from where the snowball is thrown, so it was thrown with speed <em>v</em> such that

2 m = <em>v </em>(0.429 s)

<em>v</em> = (2 m) / (0.43 s)

<em>v</em> ≈ 4.7 m/s

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