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3 years ago

I need help ASAP PLEASE!!!

Physics

1 answer:

Setler79 [48]3 years ago

3 0

Answer:

A. O and Fe

Explanation:

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On a journey of 600 km, a train was delayed 1 hour and 30 min after having covered 1 4 of the way. To arrive on time at the dest

mars1129 [50]

Answer:

The train travelled 10hours.

Explanation:

Using speed= distance/time ...eq1

Let the time taken by train to cover the journey be t.

Let the speed of train be s

Time= distance/speed ...eq2

Time t =600/s ...eq3

The train is delayed for 1 1/2 hours=3/2 hours

Train increased by 15km/hr.

Train travelled 1/4 of 600k.= 150km.

Speed increased by s + 15 to cover the remaining 450km

t = 150/s + 400/(s + 15) + 3/2 ..eq4

Equating eq3 and 4

600/s= 150/s + 460/(s + 15) + 3/2

450/s = 3/2 + 450/(s + 15)

3s^2 + 45s -13500=0

Solving the quadratic equation

S= -45 +-sqrt(45^2-4(3×13500)/2×3

S= 60 , -75

Hence speed of train is 60km/hr

Using eq 2 distance/speed=time

600/60=10

t= 10hours

5 0

3 years ago

What is the working principle of an electric motor?

slava [35]

The answer B homie trust

5 0

3 years ago

Read 2 more answers

A car is traveling at 15m/s on a horizontal road. the brakes are applied and the car skids to a stop in 4.0s . the coefficient o

iren2701 [21]

Answer:

the coefficient of Kinetic friction between the tires and road is 0.38

Option A) .38 is the correct answer

Explanation:

Given that;

final velocity v = 0

initial velocity u = 15m/s

time taken t = 4 s

acceleration a = ?

from the equation of motion

v = u + at

we substitute

0 = 15 + a × 4

acceleration a = -15/4 = - 3.75 m/s²

the negative sign tells us that its a deacceleration so the sign can be ignored.

Deacceleration due to friction a = μ × g

we substitute

3.75 = μ × 9.8

μ = 3.75 / 9.8 = 0.3826 ≈ 0.38

Therefore the coefficient of Kinetic friction between the tires and road is 0.38

Option A) .38 is the correct answer

8 0

3 years ago

The electric field inside a cell membrane is 8.0 MN/C. Part A What's the force on a singly charged ion in this field?

dlinn [17]

Answer:

Force on the singly charged ion will be $12.6\times 10^{-13}N$

Explanation:

We have given electric field E = 8 MN/C

So electric field in N/C will be $E=8MN/C=8\times 10^6N/C$

It is given that ion so charge on ion will be equal to $e=1.6\times 10^{-19}C$

We have to find the electric force on the ion

Electric force is equal to $F=qE$ , here q is charge and E is electric field

So force on the charge will be equal to $F=8\times 10^6\times 1.6\times 10^{-19}=12.6\times 10^{-13}N$

So force on the singly charged ion will be $12.6\times 10^{-13}N$

7 0

3 years ago

What is the difference between output and input forces

seropon [69]

Output Force- the force exerted on an object by a simple machine

Input Force- the initial force used to get a machine to begin working.

Input Force represents the amount of force that you put into another object. Output Force represents the force that a specific object has as a result of the input force.

- Hope this Helps :)

7 0

3 years ago