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3 years ago

10

Determine the mass of the object below to the correct degree of precision.

1 answer:

dedylja [7]3 years ago

3 0

For this question place the object on the scale and move the slides to change the mass until it is level. That will tell you the mass.

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Water with a volume flow rate of 0.001 m3/s, flows inside a horizontal pipe with diameter of 1.2 m. If the pipe length is 10m an

galben [10]

Answer:

$\triangle P=1.95*10^{-4}$

Explanation:

Mass $m=0.001$

Diameter $d=1.2m$

Length $l=10m$

Generally the equation for Volume flow rate is mathematically given by

$Q=AV$

$V=\frac{Q}{\pi/4D^2}$

$V=\frac{0.001}{\pi/4(1.2)^2}$

$V=8.84*10^{-4}$

Generally the equation for Friction factor is mathematically given by

$F=\frac{64}{Re}$

Where Re

Re=Reynolds Number

$Re=\frac{pVD}{\mu}$

$Re=\frac{1000*8.84*10^{-4}*1.2}{1.002*10^{-3}}$

$Re=1040$

Therefore

$F=\frac{64}{Re}$

$F=\frac{64}{1040}$

$F=0.06$

Generally the equation for Friction factor is mathematically given by

$Head loss=\frac{fLv^2}{2dg}$

$H=\frac{0.06*10*(8.9*10^-4)^2}{2*1.2*9.81}$

$H=19.9*10^{-9}$

Where

$H=\frac{\triangle P}{\rho g}$

$\triangle P=\frac{19.9*10^{-9}}{10^3*(9.81)}$

$\triangle P=H*\rho g$

$\triangle P=1.95*10^{-4}$

6 0

3 years ago

About where is our solar system located within the milky way galaxy?

sashaice [31]

Solar system is nested nearly 2/3 of the way from the center of the galaxy to the outskirt of the galactic disc.

6 0

3 years ago

A car, moving along a straight stretch of highway, begins to accelerate at 0.0323 m/s 2 . It takes the car 63.3 s to cover 1 km.

rosijanka [135]

X=ut+0.5at²
1000 = 63.3u + 0.5 * 0.0323 * 63.3²
u = (1000 - 0.1615*63.3²)/63.3
u = 5.57 m/s

i don't even know if this is correct

7 0

4 years ago

Reactance Frequency Dependence: Sketch a graph of the frequency dependence of a resistor, capacitor, and inductor. RLC Circuit R

jolli1 [7]

Answer:

$f=\frac{1}{2\pi \sqrt{LC}}$

Explanation:

We know that impedance of a RLC circuit is given by $Z=R+J(X_L-X_C)$

So $Z=\sqrt{R^2+(X_L-X_C)^2}$ here R is resistance $X_L$ is inductive reactance and $X_C$ is capacitive reactance

To minimize the impedance $X_L-X_C$ should be zero we know that $X_L=\omega L\ and \ X_C=\frac{1}{\omega C}$

So $\omega L-\frac{1}{\omega C}=0$

$\omega ^2=\frac{1}{LC}$

$\omega =\sqrt{\frac{1}{LC}}$

We know that $\omega =2\pi f$

So $\omega =2\pi f=\frac{1}{\sqrt{LC}}$

$f=\frac{1}{2\pi \sqrt{LC}}$

Where f is resonance frequency

8 0

3 years ago

A guitar string is 0.620 m long, and

miskamm [114]

Answer:

The answer to this problem is 290.16m/s

3 0

3 years ago