<u>Answer:</u>
The given statement is a True statement
<u>Explanation:</u>
All cars and trucks have load capacities marked on the jamb of the driver's door, as well as the owner's manual.
This is very significant for braking distance.
A heavier object will require much more braking force and distance to stop, due to New ton's law of motion. “ An object in motion will tend to stay in motion “ .A heavy object will remain in motion longer and require much more force to stop. Four wheel disc brakes are great compared to front disc and rear drum configuration, in dissipating heat, and stopping more efficiently.
Answer:
current in series is 2.50 mA
current in parallel is 13.51 mA
Explanation:
given data
voltage = 5 V
resistors R1 = 1.5 kilo ohms
resistors R2 = 0.5 kilo ohms
to given data
current flow
solution
current flow in series is express as here
current = voltage / resistor .................1
put here all value in equation 1
current = 5 / (1.5 + 0.5)
current = 5 / 2.0
so current = 2.50 mA
and
current flow in parallel is express as
current = voltage / resistor ....................2
put here all value in equation 2
current = 5 / (1/ (1/1.5 + 1/0.5))
current = 5 / 0.37
so current = 13.31 mA
Answer:
15.8 V
Explanation:
The relationship between capacitance and potential difference across a capacitor is:

where
q is the charge stored on the capacitor
C is the capacitance
V is the potential difference
Here we call C and V the initial capacitance and potential difference across the capacitor, so that the initial charge stored is q.
Later, a dielectric material is inserted between the two plates, so the capacitance changes according to

where k is the dielectric constant of the material. As a result, the potential difference will change (V'). Since the charge stored by the capacitor remains constant,

So we can combine the two equations:

and since we have
V = 71.0 V
k = 4.50
We find the new potential difference:

Answer:
a) t = 4.16 s
b) x = 141.51 m
Explanation:
Given
v = 21.5 m/s
x0 = 52.0 m
a = 6.0 m/s²
a) Motorcycle
x = v0*t + (a*t²/2)
x = 21.5t + (6*t²/2)
x = 21.5t + 3t² <em>(I)</em>
Car
x = x0 + v0*t
x = 52 + 21.5t <em>(II)</em>
<em />
then we can apply <em>I = II</em>
21.5t + 3t² = 52 + 21.5t
⇒ 3t² = 52
⇒ t = 4.16 s
b) We can use <em>I</em> or <em>II</em>, then
x = 52 + 21.5*(4.16)
⇒ x = 141.51 m