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RSB [31]
3 years ago
14

The possible products of a double displacement reaction in aqueous solution are SrSO4 and NaCl. Which of these possible products

will form as a solid in this reaction? Question 8 options: A) SrSO4 B) Neither compound will form as a solid C) Both compounds will form as a solid D) NaCl
Chemistry
1 answer:
madam [21]3 years ago
7 0

Answer:

SrSO4

Explanation:

According to solubility rules, we know that the sulphates of the elements of group two are insoluble in water. The solubility rules describe what chemical species are soluble in water and what species are not soluble in water.

Generally, all chlorides are soluble in water with exception of chlorides such as silver chloride. The chlorides of group one elements are usually highly soluble in water.

Since SrSO4 is a sulphate of a group two element (strontium) it will be the insoluble solid product of the double displacement reaction described in the question.

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1) d

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3 years ago
The reaction A + 2B → products was found to follow the rate law: rate = k[A] 2[B]. Predict by what factor the rate of reaction w
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A + 2B → products

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rate = k[A]²[B]

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