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RSB [31]
2 years ago
14

The possible products of a double displacement reaction in aqueous solution are SrSO4 and NaCl. Which of these possible products

will form as a solid in this reaction? Question 8 options: A) SrSO4 B) Neither compound will form as a solid C) Both compounds will form as a solid D) NaCl
Chemistry
1 answer:
madam [21]2 years ago
7 0

Answer:

SrSO4

Explanation:

According to solubility rules, we know that the sulphates of the elements of group two are insoluble in water. The solubility rules describe what chemical species are soluble in water and what species are not soluble in water.

Generally, all chlorides are soluble in water with exception of chlorides such as silver chloride. The chlorides of group one elements are usually highly soluble in water.

Since SrSO4 is a sulphate of a group two element (strontium) it will be the insoluble solid product of the double displacement reaction described in the question.

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50 examples word equation with balanced chemical equarion​
gulaghasi [49]
This question may only be ansewered by frequent mattrrs
5 0
1 year ago
PLEASE HELP ME
ki77a [65]

Answer:

1.15 atm

Explanation:

According to Dalton's law of partial pressures, the total pressure is the sum of all the partial pressures of the gases present in the mixture.

Therefore we have:

Total pressure = partial pressure of carbon monoxide + partial pressure of oxygen + partial pressure of carbon dioxide

We were given the following:

Total pressure = 2.45 atm

Pressure of oxygen = 0.65 atm

Pressure of carbon monoxide = x

Pressure of carbon dioxide = 0.65 atm

Therefore:

2.45 = x + 0.65 + 0.65

2.45 = x + 1.3

x = 2.45 - 1.3

x = 1.15 atm

6 0
3 years ago
Proportional means that
FromTheMoon [43]
Corresponding in size or amount to something else.
5 0
3 years ago
5. If 1 g of a gas occupies a volume of 300 mL at STP, what is the molecular weight of the gas?
ikadub [295]

Answer:

74,67 gr/mol

Explanation:

At STP 1 mole of an ideal gas has volume of 22,4 L. Since we know the volume of the gas we can find the number of moles of the gas. (300 mL=0,3 L)

n=0,3L/22,4 L=0,01339 mol

Since we know weight of the gas as 1 g, we can find the molecular weight as;

MW=1 g/0,01339 mol =74,67 gr/mol

3 0
2 years ago
(f) Which of the following alkenes is the major product when 2-bromo-2-methylpentane is treated with sodium ethoxide in ethanol?
belka [17]

Answer:

D) 2-methylpent-2-ene

Explanation:

This is an elimination reaction of Halogenoalkane. 2-bromo-2-methylpentane when is heated with NaOH or NaOC2O5( sodium ethoxide) in ethanol will form alkene rather than alcohol.

2-methylpent-1-ene is minor product since double bond form with secondary Carbon rather than primary Carbon.

8 0
3 years ago
Read 2 more answers
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