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matrenka [14]
3 years ago
13

A bat can detect small objects, such as an insect, whose size is approximately equal to one wavelength of the sound the bat make

s. If bats emit a chirp at a frequency of 5.59 104 Hz, and if the speed of sound in air is 343 m/s, what is the smallest insect a bat can detect?Answer in units of mm
Physics
2 answers:
blsea [12.9K]3 years ago
8 0

Answer:

6.136 mm

Explanation:

given,

frequency emitted by the bat = 5.59 x 10⁴ Hz

speed of sound = 343 m/s

smallest insect bat can hear  will be equal to the wavelength  of the sound the bat make.

\lambda = \dfrac{v}{f}

\lambda = \dfrac{343}{5.59\times 10^4}

\lambda = 6.136\times 10^{-3}}

λ = 6.136 mm

so, the smallest size of insect that bat can hear is equal to 6.136 mm

____ [38]3 years ago
6 0
<h2>The smallest insect a bat can detect is of size 6.13 mm</h2>

Explanation:

Velocity = Wavelength x Frequency

v = fλ

Velocity of sound, v = 343 m/s

Frequency, f = 5.59 x 10⁴ Hz

Substituting

             343 =  Wavelength x 5.59 x 10⁴

             Wavelength = 6.13 x 10⁻³ m = 6.13 mm

A bat can detect small objects, such as an insect, whose size is approximately equal to one wavelength of the sound the bat makes.

The smallest insect a bat can detect is of size 6.13 mm

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6 0
3 years ago
A car battery has a rating of 250 ampere-hours. This rating is one indication of the total charge that the battery can provide t
Serga [27]

Answer:

Total charge provided by the battery could be 900000 C.

Maximum current provided by the battery for 37 minutes could be 405.405 A

Explanation:

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a. Total charge:

Rating=Q/t\\Q=Rating.t\\

Suppose t=1h

Q=250 A(1h)\\Q=250 A(3600 sec)\\Q= 900000 A.sec

We konw that Ampere=\frac{Coulomb}{sec}, replacing:

Q=900000(\frac{Coulomb}{sec})(sec)\\Q=900000 Coulomb

Total charge provided by the battery could be 900000 C.

b. Maximum current for 37 minutes

I=\frac{Q}{t} \\I=\frac{900000 C}{37*60 sec}\\I=405.405 A

Maximum current provided by the battery for 37 minutes could be 405.405 A

4 0
3 years ago
Space debris left from old satellites and their launchers is becoming a hazard to other satellites. (a) Calculate the speed of a
Pie

Answer:

Part a)

v = 7407.1 m/s

Part b)

v_{rel} = 1.05 \times 10^4 m/s

Explanation:

Part a)

As we know that orbital velocity at certain height from the surface of Earth is given as

v = \sqrt{\frac{GM}{R+h}}

here we know that

M = 5.98 \times 10^{24} kg

R = 6.37 \times 10^6 m

h = 900 km = 9.0 \times 10^5 m

now we have

v = \sqrt{\frac{(6.67 \times 10^{-11})(5.98 \times 10^{24})}{6.37 \times 10^6 + 9.0 \times 10^5}}

v = 7407.1 m/s

Part b)

When a loose rivet is moving in same orbit but at 90 degree with the previous orbit path then in that case the relative speed of the rivet with respect to the satellite is given as

v_{rel} = \sqrt{2} v

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6 0
3 years ago
Which situation will change the direction of the bicycle?
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Answer:

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Explanation:

6 0
3 years ago
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Answer:

K = 588.3 N/m

Explanation:

From a forces diagram, and knowing that for the maximum value of K, the crate will try to rebound back up (Friction force will point downward):

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X = \frac{Ff + W*sin(22)}{K}=\frac{1223}{K}

By conservation of energy:

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Replacing our previous value for X and solving the equation for K, we get maximum value to prevent the crate from rebound:

K = 588.3 N/m

6 0
3 years ago
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