Work done = force × distance travelled in the direction of the force
Force= 2(9.81) = 19.62N
WD= 19.62×130= 2550.6Nm
Answer:
s=0.36m part c lands
Explanation:
from conservation of linear momentum
we know that
the momentum before Collision(explosion) is equal to the momentum after collision( explosion)
0=maua+mbub+mcuc
ma=.5kg
mb=.5kg
mc=9.8-(0.5+0.5)
mc=8.8kg
since the fragments all fall to the ground at the same time, we assume same time for all
t=0.27s
the velocity of a
v=u +at
since it falling stariaght down
v=0+9.81*.27
v=2.64m/s is the vertical side of its velocity
, since its falling straight down , the horizontal velocity is zero
the velocity of b
s=ut horizontal component of the distance
6.5=.27*ub
ub=24.07m/s
from
0=maua+mbub+mcuc
0=0.5*0+0.5*24.07+8.8*cu
uc=1.36
the distance from a will be
s=ut
s=1.36*.27
s=0.36m
Answer:
Particles of the medium are displaced completely from their initial positions, moving along with the wave front
Explanation:
i did the test
The magnitude of the acceleration in the y-direction is
Explanation:
When a projectile is fired into the air, there is only one force acting on it (neglecting air resistance): the force of gravity, which pulls the projectile downward with a force of
F = mg
where m is the mass of the projectile and is the magnitude of the acceleration of gravity. This force acts along the y-direction, downward.
Since there are no other forces acting, therefore, the motion of the projectile consists of two separate motions:
- A uniform motion along the x-direction, with constant velocity
- A uniformly accelerated motion along the y-direction, with constant acceleration ()
So, the magnitude of the acceleration in the y-direction is .
Learn more about projectile motion:
brainly.com/question/8751410
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The electrons are already there. They are freely moving through the conductor.