Ask question

Ask question

All categories

3 years ago

8

How does the law of conservation of energy apply to machines?

2 answers:

viva [34]3 years ago

5 0

whats the answer choice like a or whatever plz and thank u

allsm [11]3 years ago

4 0

Energy can be changed from one form to another, but it cannot be created or destroyed. ... This principle is referred to as the first law of thermodynamics or the law of energy conservation. The law applies to all systems both large and small, and, again, it states that energy cannot be created or destroyed.

You might be interested in

PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer these correctly!!!! (40pts)

Sunny_sXe [5.5K]

friction make non moving objects starts to move

true

there are different types of force which may help them to move

3 0

3 years ago

For an object to orbit another object

STatiana [176]

B. Inertia and gravity must be balanced.

8 0

3 years ago

CAN SOMEONE TELL ME THE answer for this ?

Paladinen [302]

Answer:

b. light from earth is reflected by the moon surface

4 0

2 years ago

Read 2 more answers

Which is the correct scientific notation for 724,000,000,000?

NikAS [45]

Answer:

Explanation:

scientific notation for 724,000,000,000 is

7.24*10^11

5 0

3 years ago

The ink drops have a mass m = 1.00×10^−11 kg each and leave the nozzle and travel horizontally toward the paper at velocity v =

luda_lava [24]

Answer:

9.98 × 10⁻⁹ C

Explanation:

mass, m = 1.00 × 10⁻¹¹ kg

Velocity, v = 23.0 m/s

Length of plates D₀ = 1.80 cm = 0.018 m

Magnitude of electric field, E = 8.20 × 10⁴ N/C

drop is to be deflected a distance d = 0.290 mm = 0.290 × 10⁻³ m

density of the ink drop = 1000 kg/m^3

Now,

Time = $\frac{\textup{Distance}}{\textup{Velocity}}$

or

Time = $\frac{\textup{0.016}}{\textup{23}}$

or

Time = 6.9 × 10⁻⁴ s

Now, force due to the electric field, F = q × E

where, q is the charge

Also, Force = Mass × acceleration

q × E = 1.00 × 10⁻¹¹ × a

or

a = $\frac{q\times8.20\times10^4}{1\times10^{-11}}$

Now from the Newton's equation of motion

$d=ut+\frac{1}{2}at^2$

where,

d is the distance

u is the initial speed

a is the acceleration

t is the time

or

$0.290\times10^{-3}=0\times(6.9\times10^{-4})+\frac{1}{2}\times(\frac{q\times8.20\times10^4}{1\times10^{-11}})\times(6.9\times10^{-4})^2$

or

q = 9.98 × 10⁻⁹ C

4 0

3 years ago