Answer:
The magnitude of the force of friction equals the magnitude of my push
Explanation:
Since the crate moves at a constant speed, there is no net acceleration and thus, my push is balanced by the frictional force on the crate. So, the magnitude of the force of friction equals the magnitude of my push.
Let F = push and f = frictional force and f' = net force
F - f = f' since the crate moves at constant speed, acceleration is zero and thus f' = ma = m (0) = 0
So, F - f = 0
Thus, F = f
So, the magnitude of the force of friction equals the magnitude of my push.
The scalar reading during the process is 170. 5 Newton
<h3>
How to determine the scalar reading</h3>
force = mass × acceleration
Given the mass = 55kg
In finding the acceleration, use the first equation of motion
v = u + at
u = 0
t = 2s
v = 6.5 m/s
Substitute the values
6.5 = 0 + 2a, make 'a' the subject
a = 6. 5÷ 2 = 3. 1 m/s²
Substitute the value of 'm' and 'a' in the original equation
F = 55× 3.1 = 170. 5 Newton
Hence, the scalar reading during the process is 170. 5 Newton
Learn more about force here:
brainly.com/question/13164598
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Properties to identify a mineral:
Color
Luster
Streak
Hardness
Cleavage
(There appears to be 8 things you need to fill in but I only know this much)
What will scratch Quartz:
Topaz
Corundum
Diamond
sorry I only knew a few of the answers, hope I still helped
They look like tiny cubes. They are in a cubic form.
Answer:
The velocity when the ball hits the ground is obtained using v2. 2 = v1. 2 + 2 g Dy with v1=0 and Dy=h. Thus solving for v2 yields 17.1 m/s v2 = 2 g h =.
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