Question

spring is compressed 4.2 cm. If a box is placed at the end of the compressed spring, and let go, how far up the ramp will the spring cause the box to travel? Ignore any frictional effects.

Answer 1

Answer:

0.81 m

Explanation:

K= 36 N/m

θ= 30°

mass m = 8 kg

let the distance moved by the box be d

We can  solve this using

Apply conservation of energy

$\frac{1}{2}kx^2= mg sin\theta\times d$

d= 1/2×k×x^2/ mg sinθ

$d= \frac{1}{2}\times36(0.042)^2/8\times9.81sin30$

d  = 0.81 m