Answer:
The value is
Explanation:
From the question we are told that
The angular speed is ![w = 2030 \ rpm = \frac{2030 * 2 * \pi }{ 60} = 212.61 \ rad/s](https://tex.z-dn.net/?f=w%20%3D%202030%20%5C%20rpm%20%3D%20%5Cfrac%7B2030%20%2A%202%20%2A%20%5Cpi%20%7D%7B%2060%7D%20%3D%20%20212.61%20%5C%20rad%2Fs)
The distance between the minimum and maximum external position is
Generally the amplitude of the crank shaft is mathematically represented as
=>
=> ![A = 0.03475 \ m](https://tex.z-dn.net/?f=A%20%3D%20%200.03475%20%5C%20%20m)
Generally the maximum speed of the piston is mathematically represented as
=> ![|v| = 0.03475 * 212.61](https://tex.z-dn.net/?f=%7Cv%7C%20%3D%200.03475%20%2A%20212.61)
=>
<h3><u>Answer;</u></h3>
A. wind, tidal, geothermal, and hydroelectric
<h3><u>Explanation</u>;</h3>
- Renewable energy sources are the energy sources that are constantly being replenished, such as sunlight, wind, and water. This means that we can use them as much as we want, and we do not have to worry about them running out.
- Additionally, renewable energy sources are usually much more environmentally friendly than fossil fuels. Examples of renewable sources of energy includes; solar energy, wind energy, hydroelectric power, tidal energy, geothermal energy, etc.
Answer:
2.36 x 10^6 J
Explanation:
Tc = 0°C = 273 K
TH = 22.5°C = 295.5 K
Qc = heat used to melt the ice
mass of ice, m = 85.7 Kg
Latent heat of fusion, L = 3.34 x 10^5 J/kg
Let Energy supplied is E which is equal to the work done
Qc = m x L = 85.7 x 3.34 x 10^5 = 286.24 x 10^5 J
Use the Carnot's equation
![\frac{Q_{H}}{Q_{c}}=\frac{T_{H}}{T_{c}}](https://tex.z-dn.net/?f=%5Cfrac%7BQ_%7BH%7D%7D%7BQ_%7Bc%7D%7D%3D%5Cfrac%7BT_%7BH%7D%7D%7BT_%7Bc%7D%7D)
![Q_{H}=286.24\times 10^{5}\times \frac{295.5}{273}](https://tex.z-dn.net/?f=Q_%7BH%7D%3D286.24%5Ctimes%2010%5E%7B5%7D%5Ctimes%20%5Cfrac%7B295.5%7D%7B273%7D)
QH = 309.8 x 10^5 J
W = QH - Qc
W = (309.8 - 286.24) x 10^5
W = 23.56 x 10^5 J
W = 2.36 x 10^6 J
Thus, the energy supplied is 2.36 x 10^6 J.
When you heat a certain substance with a difference of temperature
![\Delta T](https://tex.z-dn.net/?f=%5CDelta%20T)
the heat (energy) you must give to it is
![E(=Q) =mc\Delta T](https://tex.z-dn.net/?f=E%28%3DQ%29%20%3Dmc%5CDelta%20T)
where
![c](https://tex.z-dn.net/?f=c)
is the specific heat of that substance (given in J/(g*Celsius))
In this case
![E=645*0.3850*(28.22-13.20) =3729.8 (Joule)](https://tex.z-dn.net/?f=E%3D645%2A0.3850%2A%2828.22-13.20%29%20%3D3729.8%20%28Joule%29)
Observation: the specific heat of a substance is given in J/(g*Celsius) or J/(g*Kelvin) because on the temperature scale a
difference of 1 degree Celsius = 1 degree Kelvin