How much 6.0 M HNO3 is needed to neutralize 39 mL of 2.0 M KOH?
2 answers:
Answer : The volume of needed are, 0.013 L
Explanation :
According to the neutralization law,
where,
= molarity of
= 6.0 M = 6.0 mole/L
= molarity of
= 2.0 M = 2.0 mole/L
= volume of
= ?
= volume of
= 39 ml = 0.039 L
conversion : 1 L = 1000 ml
Now put all the given values in the above formula, we get the volume of
Therefore, the volume of needed are, 0.013 L
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Answer:
The four resonance structures of the phenoxide ion are shown in the image attached
The conjugate base of cyclohexanol has only one resonance contributor, while
the conjugate base of phenol has four resonance contributors.
Explanation:
In organic chemistry, it is known that structures are more stable if they possess more resonance contributors. The greater the number of contributing canonical structures, the more stable the organic specie. Since the phenoxide ion has four contributing canonical structures, it is quite much more stable than cyclohexanol having only one contributing structure to its conjugate base. Hence the PKa(acid dissociation constant) of phenol is lesser than that of cyclohexanol. The conjugate base of phenol is stabilized by resonance.
