How much 6.0 M HNO3 is needed to neutralize 39 mL of 2.0 M KOH?
2 answers:
Answer : The volume of needed are, 0.013 L
Explanation :
According to the neutralization law,
where,
= molarity of
= 6.0 M = 6.0 mole/L
= molarity of
= 2.0 M = 2.0 mole/L
= volume of
= ?
= volume of
= 39 ml = 0.039 L
conversion : 1 L = 1000 ml
Now put all the given values in the above formula, we get the volume of
Therefore, the volume of needed are, 0.013 L
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Answer : The correct option is, (C) 6
Explanation :
Oxidation-reduction reaction : It is a reaction in which oxidation and reduction reaction occur simultaneously.
Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.
Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.
The given unbalanced chemical reaction is,
Half reactions of oxidation and reduction are :
Oxidation : ......(1)
Reduction : .......(2)
In order to balance the electrons, we multiply equation 1 by 2 and equation 2 by 3, we get:
Oxidation : ......(1)
Reduction : .......(2)
The overall balanced chemical reaction will be:
From this reaction we conclude that the electrons are getting transferred from iron to iodine and the number of electrons transferred are 6 electrons.
Hence, the correct option is, (C) 6