Answer: a) 
b) 
Explanation:
A nuclear fission reaction is defined as the reaction in which a heavy nucleus splits into small nuclei along with release of energy.
a) The given reaction is 
Now, as the mass on both reactant and product side must be equal:


Thus three neutrons are produced and nuclear equation will be: 
b) For the another fission reaction:

To calculate A:
Total mass on reactant side = total mass on product side
235 + 1 = A + 94 + 2
A = 140
To calculate Z:
Total atomic number on reactant side = total atomic number on product side
92 + 0 = 56 + Z + 0
Z = 36
As Krypton has atomic number of 36,Thus the nuclear equation will be :

Answer:
72.04 dB.
Explanation:
The intensity level of 60dB corresponds to the sound intensity
given by the equation

where 
solving for
we get:



Now, when 16 violins are playing the intensity
becomes

which on the decibel scale gives

.
Thus, playing 16 violins together gives the intensity level of 72 dB.
The electrons are removed from the rod and transferred to the silk cloth. This leaves the rode positively charged and the cloth negatively charged.
To find the maximum height we use the expression:
U²=2gh
Where u is the initial velocity,
g is gravitational field strength
h is the maximum height.
h=u²/2g
h=40²/20
=1600/20
=80m
Answer:
C,
Explanation:
I'm not sure because I'm not familiar with this topic ,,,make your own answer if I am wrong.