Answer:
<em>126.01 rad/s^2</em>
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Explanation:
since it starts from rest, initial angular speed ω' = 0 rad/s
angular speed N = 477 rev/min
angular speed in rad/s ω = =
= 49.95 rad/s
angular displacement ∅ = 1.5758 rev
angular displacement in rad/s = = 2 x 3.142 x 1.5758 = 9.9 rad
angular acceleration = ?
using the equation of angular motion
ω^2 = ω'^2 + 2∅
imputing values, we have
2495 = 19.8
= 2495/19.8 = <em>126.01 rad/s^2</em>
Answer:
Explanation:
The motion of a projectile consists of two independent motions:
- A uniform motion along the horizontal direction (constant velocity)
- A uniformly accelerated motion along the vertical direction (constant acceleration)
The time of flight of a projectile is given by
where
is the initial vertical velocity
is the acceleration due to gravity
Here the time of flight is
t = 8 s
So, the initial vertical velocity is:
At the same time, the horizontal distance covered by the projectile is given by
where
is the horizontal velocity, which is constant
t is the time of flight
Here we know that the range of the projectile is 0.3 km, so
d = 0.3 km = 300 m
So the horizontal velocity is
Therefore, we can find the angle of projection of the projectile by using:
Answer:
v = 61.54 km/h
Explanation:
The average speed of the car can be found by using the total distance covered by the car and the total time taken for that distance to be traveled. Therefore, the average speed of the car can be found by the following formula:
where,
v = average speed during the trip = ?
d = total distance driven by the car = 1200 km
t = time taken for the traveling = 19.5 hr
Therefore,
<u>v = 61.54 km/h</u>