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Anastaziya [24]

2 years ago

13

A 15kg object is travelling 10m/s and hit a stationary 10kg object and stuck together. What is the final velocity of the objects

?

1 answer:

qaws [65]2 years ago

7 0

Answer:

first object final velocity =2m/s

second = 12m/s

Explanation:

i hope this will help you,..,

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A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o

Ksju [112]

Answer:

71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

$f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz$

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

$\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m$

The fundamental frequency of the wire is given by

$f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N$

The tension in the wire is 67.9064 N

7 0

2 years ago

A boy weighs 50 kg and is running with 225 J of energy, what is his velocity?

Oksanka [162]

0.22

Explanation:

50 ÷ 225 = 0.22

<u>#CarryOnLearning</u>

8 0

2 years ago

Read 2 more answers

Can anyone help??????????????

DerKrebs [107]

I think the answer should be the last one. Magnets attract magnets with unlike poles and repel magnets with like poles

3 0

3 years ago

What happens when a substance absorbs light?

Anna11 [10]

<span>One of three things the photon passes through unscathed, the photon gets absorbed by the electron of an atom and stays put, or the photon gets absorbed and a second generation photon is generated by that electron</span>

7 0

3 years ago

Starting from rest, a 88-kg firefighter slides down a fire pole. The average frictional force exerted on him by the pole has a m

Cloud [144]

Answer:h=7.22 m

Explanation:

Given

mass of firefighter $m=88 kg$

Frictional Force $F=800 N$

average speed at bottom $v=3.2 m/s$

Let h be the height of Pole

net force on Firefighter is

$F_{net}=88\times 9.8-800=62.4$

therefore net acceleration is

$a_{net}=\frac{62.4}{88}=0.709 m/s^2$

using $v^2-u^2=2ah$

here $v=3.2 m/s$

$u=0$

$(3.2)^2-0=2\times 0.709\times h$

$h=\frac{10.24}{1.418}$

$h=7.22 m$

3 0

3 years ago