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umka2103 [35]
4 years ago
12

4. A teacher throws the stapler at her students 23 m in 1.2 seconds. What speed must the teacher throw the

Physics
1 answer:
Mnenie [13.5K]4 years ago
8 0

Answer:

dy

Explanation:

My guess of guts.

okay bye

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How does the Doppler effect cause a siren's pitch to increase as it
Likurg_2 [28]

Answer:

Sound waves are pushed closer together, decreasing wavelength

and increasing frequency.

5 0
3 years ago
A bag weighing 20 N is pushed horizontally a distance of 35 m across a
topjm [15]

Answer:

350J

Explanation:

Given parameters:

Weight of bag  = 20N

Distance moved horizontally  = 35m

Force applied  = 10N

Unknown:

Work done on the bag  = ?

Solution:

Work done is the force applied to move a body through given distance.

  Work done  = Force applied x distance

So;

 Work done  = 10 x 35  = 350J

6 0
3 years ago
A small plane flies 37.0 km in a direction 45° north of east and then flies 28.0 km in a direction 25° north of east.
Karo-lina-s [1.5K]

Answer:

d= 64.1 km θ = 36.4º

Explanation:

a) In order to find the plane's straight-line distance from the starting point, we need to know the coordinates of the final and initial position of the plane, so we can find the total displacement, as the difference between the final and initial position.

If we choose to put our origin at the initial point of trajectory, we have that (x₀, y₀) = (0, 0)

In order to find the position of the plane after finishing the flight, we need to find its final coordinates (x₁, y₁).

In order to get x₁, we need to add the x-coordinate after flying 45º north of east, and the Δx after  completing the flight in a direction 25º of east, that we can find applying trigonometry, as follows:

x₁ = 37.0 km * cos 45º + 28.0 km* cos 25º = 51.6 Km

Appying the same considerations for the y-coordinate, we have:

y₁ = 37.0 km * sin 45º + 28.0 km* sin 25º = 38.0 km

Now, as the initial position coincides with the origin, the distance in a straight line from this point to the origin, is just the hypotenuse of the triangle determined by the coordinates (x₁, y₁) and (0,0), as follows:

d = \sqrt{x1^{2}+y1^{2}} =\sqrt{(51.6km)^{2}+(38km)^{2}} =64.1 km

The geographic direction of the displacement vector (which coincides in magnitude with the distance we have just found), is just the angle that this distance forms with the east axis, that we can find getting the tangent of this angle as follows:

tg θ =\frac{y1}{x1} = \frac{38km}{56.1km} =0.736

⇒ θ = 36.4º North of East (counterclockwise from the east axis).

7 0
3 years ago
Sagutin ang mga sumusunod na tanong. Isulat ang iyong sagot sa sagutang papel.
Maru [420]

Answer:

ang mga nota opo naipalakpak ko ng maayos

7 0
3 years ago
Developing a question for appointments
AlexFokin [52]

Explanation:

how can I help you that?

8 0
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