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3 years ago

5

Simplify and leave in radical form.

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1 answer:

ikadub [295]3 years ago

6 0

Answer: 0.0

Step-by-step explanation:

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For the following exercise, determine the range (possible values) of the random variable, X. A batch of 300 machined parts conta

solmaris [256]

Answer:

{0,1,2,3,4,5}

Step-by-step explanation:

We are given that

Total number of machine parts=300

Number of defective machine parts=10

Total number of good machine parts=300-10=290

Sample contain parts that do not conform to customer requirement=5

X is a random variable which is the number of parts in a sample of 5 parts that do not conform to customer requirements.

We have to find the correct answer.

The sample contain 5 parts

Therefore, the possible values of random variable X

0,1,2,3,4,5

Hence, the range of X is given by

{0,1,2,3,4,5}

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3 years ago

What numbers do 9 12 6 3 and 5 go into

KiRa [710]

It wont be a perfect number

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2 years ago

9a + 18c. What is the value of the expression when a = −5 and c = −1?

saw5 [17]

1. plug in the numbers for the variables, like this: 9(-5)+18(-1)

2. solve
Hopefully this helps! Let me know if you need more explanation.

4 0

2 years ago

Is there enough information to prove that the triangles are congruent?

olasank [31]

Answer:

Yes, there is enough information to prove that the triangles are congruent.

SAS POSTULATE

Step-by-step explanation:

$In\:\triangle ABC \: and \triangle XYZ\\$

$AB\cong XY..... (given) \\$

$\angle ABC \cong\angle XYZ\\(each \: 90\degree) \\$

$BC\cong YZ..... (given) \\$

$\therefore \triangle ABC \cong \triangle XYZ\\(SAS\: postulate)$

7 0

2 years ago

Read 2 more answers

The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.917 g and a standard deviation

Nutka1998 [239]

Answer:

$z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903$

And we can find this probability to find the answer:

$P(z$

And using the normal standar table or excel we got:

$P(z$

Step-by-step explanation:

Let X the random variable that represent the amounts of nocatine of a population, and for this case we know the distribution for X is given by:

$X \sim N(0.917,0.303)$

Where $\mu=0.917$ and $\sigma=0.303$

We have the following info from a sample of n =37:

$\bar X= 0.872$ the sample mean

And we want to find the following probability:

$P(\bar X \leq 0.872)$

And we can use the z score formula given by;

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for the value of 0.872 we got:

$z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903$

And we can find this probability to find the answer:

$P(z$

And using the normal standar table or excel we got:

$P(z$

6 0

3 years ago