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a_sh-v [17]
3 years ago
14

The pressure 75.0 meters underwater is 837 kpa. What is this pressure in mmhg

Chemistry
1 answer:
spin [16.1K]3 years ago
7 0
<h3>Answer:</h3>

                 6278 mmHg

<h3>Explanation:</h3>

Kilopascal (kPa) and Millimeter of Mercury (mm Hg) are both the units of Pressure. In medical science the pressure is often measured in mm of Hg.

Also,

                 0.133322387415 kPa equals  =  1 mmHg equals

Then,

                       837 kpa will be equal to  =  X mmHg

Solving for X,

                     X =  (837 kPa × 1 mmHg) ÷ 0.133322387415 kPa

                     X  =  6278.0153898 mmHg

Or when rounded to 4 significant numbers,

                     X  =  6278 mmHg

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5 0
4 years ago
A mixture of nitrogen and hydrogen gases, at a total pressure of 663 mm Hg, contains 3.46 grams of nitrogen and 0.156 grams of h
STALIN [3.7K]

<u>Answer:</u> The partial pressure of nitrogen gas is 405.76 mmHg and that of hydrogen gas is 257.24 mmHg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

  • <u>For nitrogen gas:</u>

Given mass of nitrogen gas = 3.46 g

Molar mass of nitrogen gas = 28 g/mol

Putting values in above equation, we get:

\text{Moles of nitrogen gas}=\frac{3.46g}{28g/mol}=0.123mol

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 0.156 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:

\text{Moles of hydrogen gas}=\frac{0.156g}{2g/mol}=0.078mol

Mole fraction of a gas is calculated by using the formula:

\chi_{A}=\frac{n_{A}}{n_{A}+n_{B}}      ......(1)

  • <u>For nitrogen gas:</u>

Putting values in equation 1, we get:

\chi_{\text{nitrogen gas}}=\frac{0.123}{0.123+0.078}=0.612

  • <u>For hydrogen gas:</u>

Putting values in equation 1, we get:

\chi_{\text{hydrogen gas}}=\frac{0.078}{0.123+0.078}=0.388

The partial pressure of a gas is given by Raoult's law, which is:

p_A=p_T\times \chi_A     ......(2)

where,

p_A = partial pressure of substance A

p_T = total pressure  = 663 mmHg

\chi_A = mole fraction of substance A

  • <u>For nitrogen gas:</u>

p_{\text{Nitrogen gas}}=663mmHg\times 0.612\\\\p_{\text{Nitrogen gas}}=405.76mmHg

  • <u>For hydrogen gas:</u>

p_{\text{Hydrogen gas}}=663mmHg\times 0.388\\\\p_{\text{Hydrogen gas}}=257.24mmHg

Hence, the partial pressure of nitrogen gas is 405.76 mmHg and that of hydrogen gas is 257.24 mmHg

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