Journal making expressing data and quantitative data
Answer:
Average atomic mass of carbon = 12.01 amu.
Explanation:
Given data:
Abundance of C¹² = 98.89%
Abundance of C¹³ = 1.11%
Atomic mass of C¹² = 12.000 amu
Atomic mass of C¹³ = 13.003 amu
Average atomic mass = ?
Solution:
Average atomic mass of carbon = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass of carbon = (12.000×98.89)+(13.003×1.11) /100
Average atomic mass of carbon= 1186.68 + 14.43333 / 100
Average atomic mass of carbon = 1201.11333 / 100
Average atomic mass of carbon = 12.01 amu.
Cart b because it has greater force and higher mass
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Hope this helps guys!
ANSWER:
What is the measured component of the orbital magnetic dipole moment of an electron with the values
(a) ml=3
(b )
ml= −4
a) -278 x
J/T
b) 3.71 x
J/T
STEP-BY-STEP EXPLANATION:
a) ml= 3
Цorb,z = ml Цв = - (3) * (9.27e - 24) = -278 x
J/T
b) ml= 3
Цorb,z = ml Цв = - (-4) * (9.27e - 24) = 3.71 x
J/T