All categories

3 years ago

Volcanic belts form along

Physics

2 answers:

zlopas [31]3 years ago

8 0

Answer;

C. the boundaries of Earth’s plates.

Explanation;

A volcanic belt is a large volcanically active region. Volcanic belts are found above zones of unusually high temperature where magma is created by partial melting of solid material in the Earth's.

Volcanic belts may be formed by multiple tectonic settings. They may be formed by subduction zones, which is an area on Earth where two tectonic plates meet and move towards one another.

andre [41]3 years ago

7 0

I believe that the correct answer is c. The boundaries of earth's plates. This is because when the plates move the mantle seeps out through the gaps the previous plate had been at this is also called seafloor spreading because as the mantle seeps up it forms new crust that pushes the other plates further apart

You might be interested in

A ball thrown straight up takes 1.89s to reach a height of 41.6m.

yulyashka [42]

Answer:

Explanation:

average velocity is 41.6/1.89 = 22.0 m/s

initial velocity u is

22.0 = (u + u - 9.81(1.89))/2

44.0 = 2u - 18.5

62.56 = 2u

u = 31.3 m/s

max height is

v² = u² + 2as

s = (v² - u²) / 2a

s = (0² - 31.3²) / (2(-9.81)) = 49.9 m

49.9 = 41.6 = 8.27 m higher

In process numbers have been rounded to 3 s.d. for reporting purposes.

8 0

3 years ago

A child with a weight of 230 N swings on a playground swing attached to 1.90 m long chains. What is the gravitational potential

nlexa [21]

Answer:

437 J

Explanation:

Parameters given:

Weight of child, W = 230 N

Height of swing, h = 1.9 m

Gravitational Potential Energy is given as:

P. E. = m*g*h = W*h

m = mass

h = height above the ground

W = weight

P. E. = 230 * 1.9

P. E. = 437 J

7 0

3 years ago

Read 2 more answers

The concept of critical density is just like the idea of escape velocity for a projectile launched from the earth. An object lau

ikadub [295]

Answer:

v = √ 2 G M/ $R_{e}$

Explanation:

To find the escape velocity we can use the concept of mechanical energy, where the initial point is the surface of the earth and the end point is at the maximum distance from the projectile to the Earth.

Initial

Em₀ = K + U₀

Final

$Em_{f}$ = $U_{f}$

The kinetic energy is k = ½ m v²

The gravitational potential energy is U = - G m M / r

r is the distance measured from the center of the Earth

How energy is conserved

Em₀ = $Em_{f}$

½ mv² - GmM / $R_{e}$ = -GmM / r

v² = 2 G M (1 / $R_{e}$ – 1 / r)

v = √ 2GM (1 / $R_{e}$ – 1 / r)

The escape velocity is that necessary to take the rocket to an infinite distance (r = ∞), whereby 1 /∞ = 0

v = √ 2GM / $R_{e}$

5 0

3 years ago

A ball is thrown straight up. What will

Papessa [141]

Answer:

velocity at the top: 0 m/s

acceleration at the top: -9.8 m/s²

Explanation:

Assuming up is positive and down is negative;

The velocity of the ball at the top of its path will be 0 m/s and the acceleration will be negative.

The velocity is 0 m/s because the ball does not move at the top of its path, and it switches from a positive velocity to a negative velocity. It must go through 0 in order to go from positive to negative.

The acceleration, however, is always negative no matter where the ball is in its motion. This negative acceleration causes the ball to slow down as it reaches the top, and speed up as it reaches the bottom.

<u>Think about it:</u> If there wasn't a negative acceleration, and it was instead 0, the ball would never come back down and instead keep going in a straight line.

6 0

2 years ago

Read 2 more answers

What is the force that the gas exerts on each of the six sides of the box when the gas temperature is 20.0∘C?

Taya2010 [7]

Incomplete question as number of moles and length is missing.So I have assumed 3 moles and length of 0.300 m.So the complete question is here:

Three moles of an ideal gas are in a rigid cubical box with sides of length 0.300 m.What is the force that the gas exerts on each of the six sides of the box when the gas temperature is 20.0∘C?

Answer:

The Force act on each side is 2.43×10⁴N

Explanation:

Given data

n=3 mol

L=0.3 m

Temperature=20.0°C=293 K

To find

Force F

Solution

To get force act on each side it would employ by

F=P.A

Where P is pressure

A is Area

First we need to find pressure by applying ideal gas law

$P.V=nRT\\P=\frac{nRT}{V}\\ P=\frac{(3mol)(8.315J/mol)(293K)}{(0.3m*0.3m*0.3m)}\\P=27.069*10^{4}Pa$

So The Force is given as:

$F=P.A\\F=(27.069*10^{4} )(0.3m*0.3m)\\F=2.43*10^{4}N$

The Force act on each side is 2.43×10⁴N

3 0

3 years ago