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m_a_m_a [10]
3 years ago
9

13. When pentane undergoes complete combustion, the products are carbon dioxide and water.

Chemistry
1 answer:
Yuki888 [10]3 years ago
4 0

Answer:

i think c

Explanation:

:D

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Need Help On this one two anybody !! pls
olga55 [171]

Answer:

26. Single Displacement

27. Synthesis

28. Decomposition

29. Combustion

30. Double Displacement

31. Combustion

32. Double Displacement

33. Decomposition

Explanation:

Hope it helped!

7 0
3 years ago
36. Write a balanced chemical equation for each chemical reaction. (a) Solid copper reacts with solid sulfur to form solid coppe
stiks02 [169]

Answer:

a) 2Cu(s) + S(s) → Cu₂S(s)

b) 2SO₂(g) + O₂(g) → 2SO₃(g)

c) 4HCl(aq) +  MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

d) C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)

Explanation:

First, we have to write the chemical formulas for reactants and products. Then, to identify which is the state of matter of each compound (liquid: l, solid: s, aqueous: aq, gas: g). Finally, we write the equation and balance the atoms.

a) Solid copper reacts with solid sulfur to form solid copper(I) sulfide.

<u>Reactants</u>: solid copper (Cu(s)) and solid sulfur (S(s))<em>. </em><u>Product</u>: copper(I) sulfide (Cu₂S) because sulfur anion has two negative charges (S⁻²) and we need two copper ions with one positive charge (Cu⁺) to obtain the neutral compound.

The balanced requires a coefficient of 2 for Cu(s) to balance the 2 Cu atoms on the products side:

2Cu(s) + S(s) → Cu₂S(s)

(b) Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas.

<u>Reactants</u>: sulfur dioxide (SO₂) and oxygen gas (which is a diatomic molecule: O₂). <u>Products</u>: sulfur trioxide gas (SO₃(s)).

The balanced equation is:

2SO₂(g) + O₂(g) → 2SO₃(g)

We need a coefficient of 2 for SO₂ and SO₃ to balance O and S atoms.

(c) Aqueous hydrochloric acid reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas.

<u>Reactants</u>: aqueous hydrochloric acid (HCl(aq)) and solid manganese (IV) oxide (MnO₂(s), because we need two oxygen anions O²⁻ to neutralize 4 positive charges in Mn IV). <u>Products</u>: aqueous manganese(II) chloride (MnCl₂, because we need two chloride ions Cl⁻ to neutralize two positive charges in Mn(II)), liquid water (H₂O), and chlorine gas (Cl₂, because it is a diatomic molecule).

The balanced chemical equation is:

4HCl(aq) +  MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

(d) Liquid benzene (C₆H₆) reacts with gaseous oxygen to form carbon dioxide and liquid water.

Reactants: benzene (C₆H₆) and gaseous oxygen (O₂). Products: carbon dioxide (CO₂, because C has valence IV) and liquid water (H₂O).

The balanced chemical equation is:

C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)

In this case, we need a coefficient of 15/2 for O₂ because on the product side there are 15 atoms of O (12 in CO₂ and 3 in H₂O).

6 0
3 years ago
According to KMT, at constant pressure and temperature, the frequency and force of molecule-wall collisions are constant. So inc
Norma-Jean [14]

Answer:

Boyle´s Law

Explanation:

If we increase the volume of a gas, its pressure will decrease that is why in this question the pressure was decreased to  yield the decrease in the number of collisions.

This is Boyle´s law which states that the pressure of a gas is inversely proportional to the volume of its container.

It is expressed mathematically  as P₁V₁ = P₂V₂

where the subscripts refer to intial and final conditions.

3 0
3 years ago
Which statment is true about incomplete dominance
yuradex [85]

Incomplete dominance occurs when neither trait is truly dominant over the other. This means that both traits can be expressed in the same regions, resulting a blending of two phenotypes. If a white and black dog produce a gray offspring, this is an example of incomplete dominance.

3 0
3 years ago
a) NaClO3 -&gt; NaCl + O2------------------------DESCOMPOSICION b) HNO3 +Fe -&gt; H2 + Fe (NO3)2------------SIMPLE SUSTITUCION c
docker41 [41]
A) <span>2 NaClO</span>₃<span>= 2 NaCl + 3 O</span>₂  ( <span>decomposition )

b) </span><span>2 HNO</span>₃ + Fe = H₂ + Fe(NO₃)₂ ( <span>single replacement )

c) 2 </span>Kl + Pb(NO₃)₂ -> Pbl₂ + 2 KNO₃ ( double replacement )

d) C + O₂ -> CO₂ ( synthesis )

e) Ca(HCO₃)₂ = CaCO₃ + CO₂ + H₂O ( <span>decomposition)

hope this helps!</span>
4 0
4 years ago
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