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UNO [17]
4 years ago
13

Salt is added to water and the mixture is stirred until no more salt dissolves. some solid salt does not dissolve and settles to

the bottom of the beaker, as shown in the figure below. what happens as the water is allowed to evaporate until the volume of solution is half the original volume? assume the temperature remains constant.
Physics
2 answers:
marta [7]4 years ago
8 0
It will get more concentrated because the amount of solvent (water) has decreased
REY [17]4 years ago
5 0

Answer:

The final concentration of salt in the solution will be two times of its initial concentration.

Explanation:

According to dilution formula:  

VC = constant  

Where,

V = Volume of solution  

C = concentration of salt in the solution  

So,  

                          V1C1 = V2C2       ………. (i)

After evaporation of water the volume of solution becomes half so,

                              V2 = V1/2        ………… (ii)  

Put equation (ii) in equation (i),

                           V1C1 = (V1/2)C2

                               C1 = C2/2

                              2C1 = C2           ...……… (iii)

Equation (iii) shows that the final concentration of salt in the solution will be two times of its initial concentration.

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The correct answer is A. Solid Rock
6 0
3 years ago
Calculate the acceleration of a 1000 kg car if the motor provides a small thrust of 1000 N and the static and dynamic friction c
grin007 [14]

Explanation :

It is given that,

Mass of the car, m = 1000 kg              

Force applied by the motor, F_A=1000\ N

The static and dynamic friction coefficient is, \mu=0.5

Let a is the acceleration of the car. Since, the car is in motion, the coefficient of sliding friction can be used. At equilibrium,

F_A-\mu mg=ma

\dfrac{F_A-\mu mg}{m}=a

a=\dfrac{1000-0.5(1000)(9.81)}{1000}

a=-3.905\ m/s^2

So, the acceleration of the car is -3.905\ m/s^2. Hence, this is the required solution.

6 0
3 years ago
I’m not sure how to solve this
spayn [35]

Answer:

Option 10. 169.118 J/KgºC

Explanation:

From the question given above, the following data were obtained:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1.61 KJ

Mass of metal bar = 476 g

Specific heat capacity (C) of metal bar =?

Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:

1 kJ = 1000 J

Therefore,

1.61 KJ = 1.61 KJ × 1000 J / 1 kJ

1.61 KJ = 1610 J

Next, we shall convert 476 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

476 g = 476 g × 1 Kg / 1000 g

476 g = 0.476 Kg

Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1610 J

Mass of metal bar = 0.476 Kg

Specific heat capacity (C) of metal bar =?

Q = MCΔT

1610 = 0.476 × C × 20

1610 = 9.52 × C

Divide both side by 9.52

C = 1610 / 9.52

C = 169.118 J/KgºC

Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC

6 0
3 years ago
In a college homecoming competition, eighteen students lift a sports car. While holding the car off the ground, each student exe
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Answer:

Explanation:

Given

Each student exert a force of F=400 N

Let mass of car be m

there are 18 students who lifts the car

Total force by 18 students F=18\times 400=7200 N

therefore weight of car W=7200

mass of car m=\frac{W}{g}

m=\frac{7200}{9.8}=734.69 kg

(b)7200 N \approx 1618.624\ Pound-force

734.69 kg\approx 1619.71 Pounds                  

6 0
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What distance will a car cover while uniformly accelerating from 12m/s to 26m/in 14 seconds​
VikaD [51]

Answer:

Distance = 266m

Explanation:

6 0
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