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eduard
3 years ago
9

Calculate the number of moles of Al2O3 that are produced when 1.2 mol of FeO is used in the following reaction.

Chemistry
1 answer:
Assoli18 [71]3 years ago
7 0

Answer:

D

Explanation:

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Each incomplete reaction is a neutralization reaction. Match each equation with the salt formed. 1. H2SO4 + 2NH4OH → ? 2. 2NaOH
sergey [27]

1. H₂SO₄ + 2NH₄OH ⟶ (NH₄)₂SO₄ + 2H₂O


2. 2NaOH + H₂CO₃ ⟶ Na₂CO₃ + 2H₂O


3. HNO₃ + KOH ⟶ KNO₃ + H₂O


<em>Explanation</em>:

Acid + base ⟶ salt + water


Take the H from the acid and the OH from the base to get water.


Then, join what’s left to get the salt. Write the symbol for the metal first.


For example, in equation 3, take the H from HNO₃ and the OH from KOH.


Combining the remaining parts (NO₃ and K) to get the salt, KNO₃.


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3 years ago
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Which of the following metals (M) will form an ionic compound with nitrogen with the general formula M3N2?
madreJ [45]
I think it’s a or b i am so not positive
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3 years ago
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in the cell, newely made proteins move directly from the ribosomes into the rough _____ _____, where they are chemically modifie
olga nikolaevna [1]

Answer:

endoplasmic reticulum

Explanation:

there it is

8 0
3 years ago
Os-191 undergoes beta decay. What would be one of the products of this reaction?
alexdok [17]

Answer:

It emits a beta particle in its nuclear decay. What is the product of the reaction that forms in 4.9 minutes? A) 1910s. 191. B) 191W. B + 191. 76. Os remember

Explanation:

7 0
1 year ago
A 52-gram sample of water that has an initial temperature of 10.0 °C absorbs 4,130 joules. If the specific heat of water is 4.18
FinnZ [79.3K]

Answer:

The final temperature of the water is 28.98 degree Celsius.

Explanation:

It is given that,

Mass of sample of water, m = 52 grams

Initial temperature, T_i=10^{\circ}C

Heat absorbed, Q=4,130\ J

The specific heat of water is 4.184\ J/(g^{\circ} C)

We need to find the final temperature of the water. The heat absorbed is given by the formula as follows :

Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\T_f=\dfrac{Q}{mc}+T_i\\\\T_f=\dfrac{4130}{52\times 4.184 }+10\\\\T_f=28.98^{\circ} C

So, the final temperature of the water is 28.98 degree Celsius.

3 0
3 years ago
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