Answer: It would be Sp2, because H3O+ has planar structure.
Answer:
I believe the answer would be A, remain 5g because heating the balloon would increase the speed of the gas molecules, but not necessarily change the amount
Answer: 1+
Justification:
The ionization energies tell the amount of energy needed to release an electron and form a ion. The first ionization energy if to loose one electron and form the ion with oxidation state 1+, the second ionization energy is the energy to loose a second electron and form the ion with oxidation state 2+, the third ionization energy is the energy to loose a third electron and form the ion with oxidation state 3+.
The low first ionization energy of element 2 shows it will lose an electron relatively easily to form the ion with oxidations state 1+.
The relatively high second ionization energy (and third too) shows that it is very difficult for this atom to loose a second electron, so it will not form an ions with oxidation state 2+. Furthermore, given the relatively high second and third ionization energies, you should think that the oxidation states 2+ and 3+ for element 2 never occurs.
Therefore, the expected oxidation state for the most common ion of element 2 is 1+.
A. It can be as important to a story as a character
C
Decreasing the wavelength increases the frequency of a wave and vice versa, as long as the energy of the wave remains constant.
Explanation:
The energy of a wave is given by the formula;
E= hf
Whereby;
E = energy
h = Plank’s constant
f = frequency
Remember that f can be also represented as;
¹/ λ
Whereby;
λ = wavelength
Wavelength and frequency are therefore inversely proportional.
Decreasing the wavelength increases the frequency of a wave and vice versa, as long as the energy of the wave remains constant.
Learn More:
For more on frequency and wavelength of waves check out;
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