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3 years ago

A pumpkin is dropped after 5 seconds its velocity is 47m/s what is its acceleration

Physics

2 answers:

ANEK [815]3 years ago

8 0

9.81m/s Hope i helped

Vesna [10]3 years ago

6 0

Answer:

Acceleration, $a=9.4\ m/s^2$

Explanation:

It is given that,

Initial speed of the pumpkin, u = 0

Final speed of the pumpkin, v = 47 m/s

Time taken, t = 5 seconds

Acceleration of an object is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{47\ m/s}{5\ s}$

$a=9.4\ m/s^2$

So, the acceleration of the pumpkin is $9.4\ m/s^2$ . Hence, this is the required solution.

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Alex17521 [72]

Max ang. speed(u) = 18 rad/s
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