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Fittoniya [83]
3 years ago
7

A pumpkin is dropped after 5 seconds its velocity is 47m/s what is its acceleration

Physics
2 answers:
ANEK [815]3 years ago
8 0
 9.81m/s Hope i helped
Vesna [10]3 years ago
6 0

Answer:

Acceleration, a=9.4\ m/s^2

Explanation:

It is given that,

Initial speed of the pumpkin, u = 0

Final speed of the pumpkin, v = 47 m/s

Time taken, t = 5 seconds

Acceleration of an object is given by :

a=\dfrac{v-u}{t}

a=\dfrac{47\ m/s}{5\ s}

a=9.4\ m/s^2

So, the acceleration of the pumpkin is 9.4\ m/s^2. Hence, this is the required solution.

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What is the value of g on the surface of Saturn? Assume M-Saturn = 5.68×10^26 kg and R-Saturn = 5.82×10^7 m.Choose the appropria
Likurg_2 [28]

Answer:

Approximately \rm 11.2 \; N \cdot kg^{-1} at that distance from the center of the planet.

Option A) The low value of g near the cloud top of Saturn is possible because of the low density of the planet.

Explanation:

The value of g on a planet measures the size of gravity on an object for each unit of its mass. The equation for gravity is:

\displaystyle \frac{G \cdot M \cdot m}{R^2},

where

  • G \approx 6.67\times 10^{-11}\; \rm N \cdot kg^{-2} \cdot m^2.
  • M is the mass of the planet, and
  • m is the mass of the object.

To find an equation for g, divide the equation for gravity by the mass of the object:

\displaystyle g = \left.\frac{G \cdot M \cdot m}{R^2} \right/\frac{1}{m} = \frac{G \cdot M}{R^2}.

In this case,

  • M = 5.68\times 10^{26}\; \rm kg, and
  • R = 5.82 \times 10^7\; \rm m.

Calculate g based on these values:

\begin{aligned} g &= \frac{G \cdot M}{R^2}\cr &= \frac{6.67\times 10^{-11}\; \rm N \cdot kg^{-2} \cdot m^2\times 5.68\times 10^{26}\; \rm kg}{\left(5.82\times 10^7\; \rm m\right)^2} \cr &\approx 11.2\; \rm N\cdot kg^{-1} \end{aligned}.

Saturn is a gas giant. Most of its volume was filled with gas. In comparison, the earth is a rocky planet. Most of its volume was filled with solid and molten rocks. As a result, the average density of the earth would be greater than the average density of Saturn.

Refer to the equation for g:

\displaystyle g = \frac{G \cdot M}{R^2}.

The mass of the planet is in the numerator. If two planets are of the same size, g would be greater at the surface of the more massive planet.

On the other hand, if the mass of the planet is large while its density is small, its radius also needs to be very large. Since R is in the denominator of g, increasing the value of R while keeping M constant would reduce the value of g. That explains why the value of g near the "surface" (cloud tops) of Saturn is about the same as that on the surface of the earth (approximately 9.81\; \rm N \cdot kg^{-1}.

As a side note, 5.82\times 10^7\rm \; m likely refers to the distance from the center of Saturn to its cloud tops. Hence, it would be more appropriate to say that the value of g near the cloud tops of Saturn is approximately \rm 11.2 \; N \cdot kg^{-1}.

6 0
3 years ago
Physical activity and exercise typically lead to
Dmitry [639]

Answer:

The answer is C (Higher energy levels)

Explanation:

Because it's C

8 0
3 years ago
Read 2 more answers
A cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains air
Ganezh [65]

Answer:

0.435atm

Explanation:

cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains air with a volume of 0.185 m3 at a pressure of 0.740 atm. The piston is slowly pulled out until the volume of the gas is increased to 0.315 m3. If the temperature remains constant, what is the final value of the pressure?

Given

Initial pressure P1= 0.740atm

Initial volume V1= 0.185 m3

Final pressure P2= ?

Final volume V2= 0.315 m3

At constant temperature, the pressure of a syste is inversely proportional to volume, by Boyles law then

P1V1=P2V2

P2=P1V1/V2

=(0.185*0.740)/0.315

0.1369/0.315

= 0.435atm

Therefore, final pressure is 0.435atm

7 0
3 years ago
HELPPPPP MEEEEE PLEASE I NEED TO SUBMIT IN LESS THAN 10 MINSS
DerKrebs [107]

Answer:

X = 2146.05 m

Explanation:

We need to understand first what is the value we need to calculate here. In this case, we want to know how far from the starting point the package should be released. This is the distance.

We also know that the plane is flying a certain height with an specific speed. And the distance we need to calculate is the distance in X with the following expression:

X = Vt   (1)

However we do not know the time that this distance is covered. This time can be determined because we know the height of the plain. This time is referred to the time of flight. And the time of flight can be calculated with the following expression:

t = √2h/g   (2)

Where g is gravity acceleration which is 9.8 m/s². Replacing the data into the expression we have:

t = √(2*2500)/9.8

t = 22.59 s

Now replacing into (1) we have:

X = 95 * 22.59

<h2>X = 2146.05 m</h2>

This is the distance where the package should be released.

Hope this helps

6 0
3 years ago
The Bay of Fundy has the greatest tidal ranges on Earth. What can you infer about the Bay of Fundy?
swat32

C is the answer

The Bay of Fundy has the greatest tidal ranges on Earth. What can you infer about the Bay of Fundy?

a.

It faces the moon more often than other places on Earth.

b.

It has many rocky beaches.

c.

It is a long, narrow inlet.

d.

Its tides cannot be predicted accurately.

4 0
3 years ago
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