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Alex777 [14]
3 years ago
11

Conversion of a continuous stream of sound into a series of ones and zeroes that can be interpreted by computers results in

Engineering
1 answer:
gayaneshka [121]3 years ago
6 0

Answer:

Conversion of a continuous stream of sound into a series of ones and zeroes that can be interpreted by computers results in  digital audio.

Explanation:

Digital audio is a portrayal of sound recorded in, or changed over into, digital structure. In digital audio, the sound flood of the audio signal is encoded as numerical examples in a persistent arrangement. In a digital audio framework, a simple electrical sign speaking to the sound is changed over with a analog-to-digital converter (ADC) into a digital sign, regularly utilizing beat code adjustment. This digital sign would then be able to be recorded, altered, adjusted, and replicated utilizing PCs, audio playback machines, and other digital apparatuses. At the point when the sound specialist wishes to tune in to the account on earphones or amplifiers (or when a shopper wishes to tune in to a digital sound record), a digital-to-analog converter (DAC) plays out the opposite procedure, changing over a digital sign go into a simple sign, which is then sent through an audio power intensifier and at last to an amplifier. Digital audio is an innovation that is utilized to record, store, control, create and repeat sound utilizing audio flags that have been encoded in digital structure. It likewise alludes to the grouping of attentive examples that are taken from a simple audio waveform. Rather than a consistent sinusoidal wave, digital audio is made out of careful focuses which speak to the sufficiency of the waveform roughly. The more examples taken, the better the portrayal, and henceforth impacts the nature of the digital audio. Most present day sight and sound gadgets can just process digital audio, and on account of mobile phones requiring simple audio input, they despite everything convert it to digital before transmission.

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A hemispherical shell with an external diameter of 500 mm and a thickness of 20 mm is going to be made by casting, located entir
Olenka [21]

Solution :

Given :

External diameter of the hemispherical shell, D = 500 mm

Thickness, t = 20 mm

Internal diameter, d = D - 2t

                                 = 500 - 2(20)

                                 = 460 mm

So, internal radius, r = 230 mm

                                 = 0.23 m

Density of molten metal, ρ = $7.2 \ g/cm^3$

                                                  = $7200 \ kg/m^3$

The height of pouring cavity above parting surface is h = 300 mm

                                                                                                  = 0.3 m

So, the metallostatic thrust on the upper mold at the end of casting is :

$F=\rho g A h$

Area, A $=2 \pi r^2$

            $=2 \pi (0.23)^2$

            $=0.3324 \ m^2$

$F=\rho g A h$

   $=7200 \times 9.81 \times 0.3324 \times 0.3$

     = 7043.42 N

3 0
3 years ago
The status of which of these determines the sequence in which output devices, such as solenoid values and motor contactors, are
Mkey [24]
A. Physical I/O sensors

Safety switches, operator inputs, travel limit switches etc
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3 years ago
What is differentiation​
oksian1 [2.3K]

Answer:

the action or process of differentiating or distinguishing between two or more things or people.

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3 years ago
Water flows through a pipe at an average temperature of T[infinity] = 70°C. The inner and outer radii of the pipe are r1 = 6 cm
Paul [167]

Answer:

The differential equation and the boundary conditions are;

A) -kdT(r1)/dr = h[T∞ - T(r1)]

B) -kdT(r2)/dr = q'_s = 734.56 W/m²

Explanation:

We are given;

T∞ = 70°C.

Inner radii pipe; r1 = 6cm = 0.06 m

Outer radii of pipe;r2 = 6.5cm=0.065 m

Electrical heat power; Q'_s = 300 W

Since power is 300 W per metre length, then; L = 1 m

Now, to the heat flux at the surface of the wire is given by the formula;

q'_s = Q'_s/A

Where A is area = 2πrL

We'll use r2 = 0.065 m

A = 2π(0.065) × 1 = 0.13π

Thus;

q'_s = 300/0.13π

q'_s = 734.56 W/m²

The differential equation and the boundary conditions are;

A) -kdT(r1)/dr = h[T∞ - T(r1)]

B) -kdT(r2)/dr = q'_s = 734.56 W/m²

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3. Which of the following is an example of qualitative data?
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Answer:

Number of Items

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