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3 years ago

Nuclear _________ reactions convert protons into helium; thus, becoming the source of all energy radiated by the sun.

Physics

2 answers:

aleksandr82 [10.1K]3 years ago

5 0

The correct answer is D) Nuclear fusion

nevsk [136]3 years ago

5 0

<h3><u>Answer;</u></h3>

Nuclear fusion

<em><u>Nuclear fusion</u></em> reactions convert protons into helium; thus, becoming the source of all energy radiated by the sun.

<h3><u>Explanation;</u></h3>

<em><u>Nuclear fusion is a type of nuclear reaction</u></em> in which two or more nuclei of atoms join to form one or more different atomic nuclei and subatomic particles.
<em><u>Nuclear fusion takes place in the sun where protons or hydrogen nuclei collide in a nuclear fusion reaction at very high temperatures to form Helium.</u></em> This nuclear fusion results in the conversion of 4 hydrogen atoms into helium atom.

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When the current in a toroidal solenoid is changing at a rate of 0.0240 A/s , the magnitude of the induced emf is 12.4 mV . When

Gemiola [76]

Answer:

The number of turns in the solenoid is 230.

Explanation:

Given that,

Rate of change of current, $\dfrac{dI}{dt}=0.0240\ A/s$

Induced emf, $\epsilon=12.4\ mV=12.4\times 10^{-3}\ V$

Current, I = 1.5 A

Magnetic flux, $\phi=0.00338\ Wb$

The induced emf through the solenoid is given by :

$\epsilon=L\dfrac{dI}{dt}$

$L=\dfrac{\epsilon}{(di/dt)}$ ........(1)

The self inductance of the solenoid is given by :

$L=\dfrac{N\phi}{I}$ .........(2)

From equation (1) and (2) we get :

$\dfrac{\epsilon}{(di/dt)}=\dfrac{N\phi}{I}$

N is the number of turns in the solenoid

$N=\dfrac{\epsilon I}{\phi (dI/dt)}$

$N=\dfrac{12.4\times 10^{-3}\times 1.5}{0.00338 \times 0.024}$

N = 229.28 turns

N = 230 turns

So, the number of turns in the solenoid is 230. Hence, this is the required solution.

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3 years ago

If 2.0×10^−4 C of charge passes a point in 2.0×10^−6 s , what is the rate of current flow?1.0×10^−10 A1.0×10^2 A4.0×10^−1 A4.0×1

Ipatiy [6.2K]

This problem is about the rate of the current. It's important to know that refers to the quotient between the electric charge and the time, that's the current rate.

$I=\frac{Q}{t}$

Where Q = 2.0×10^−4 C and t = 2.0×10^−6 s. Let's use these values to find I.

$\begin{gathered} I=\frac{2.0\times10^{-4}C}{2.0\times10^{-6}\sec } \\ I=1.0\times10^{-4-(-6)}A \\ I=1.0\times10^{-4+6}A \\ I=1.0\times10^2A \end{gathered}$

<em>As you can observe above, the division of the powers was solved by just subtracting their exponents.</em>

<em />

<h2>Therefore, the rate of the current flow is 1.0×10^2 A.</h2>

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1 year ago

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2 years ago

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oksian1 [2.3K]

Answer:

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3 years ago

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Serggg [28]

Answer:

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