The velocity at the maximum height will always be 0. Therefore, you will count your final velocity as 0, and your initial velocity as 35 m/s. Next, we know that the acceleration will be 9.8 m/s^2. How? Because the ball is thrown directly upward, and the only force acting on it will be the force of gravity pushing it back down.
The formula we use is h = (Vf^2 - Vi^2) / (2*-9.8m/s^2)
Plugging everything in, we have h = (0-1225)/(19.6) = 62.5 meters is the maximum height.
Answer: Yes.
Explanation:
Assuming Earth and Moon are isolated is space, it is possible to have a point where Earth and Moon will pull at an object with equal force.
That point will be closer to the Moon than the Earth because Moon's gravitational field strength is weaker than Earth's gravitational field strength.
Answer:
926 N
Explanation:
Metric unit conversion:
R = 18 cm = 0.18 m
r = 5 cm = 0.05 m
The pressure exerted by the F = 12000N car on the wider arm would be ratio of the gravity over area

The pressure must be the same on the smaller pressure for it to be able to start lifting the car. We can calculate the force f acting on it:

Answer:
Current amplitude, I = 5.57 A
Explanation:
It is given that,
Effective resistance, R = 22 ohms
Inductive reactance, L = 72 ohms
Voltage of the alternating source, V = 420 volt
The total impedance of the RL circuit is given by :


Z = 75.28 ohms
From Ohm's law,



I = 5.57 A
So, the current amplitude of the electric motor is 5.57 A. Hence, this is the required solution.
Answer:
SI=
How far d does the person travel during the collision if the car was initially moving forward at 4.50 km/h ?
d=