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vodomira [7]
4 years ago
9

Pascal has 96 miles remaining to complete his cycling trip. If he reduced his current speed by 4 miles per hour, the remainder o

f the trip would take him 16 hours longer than it would if he increased his speed by 50%. What is his current speed?
Physics
1 answer:
Verdich [7]4 years ago
6 0

Answer:

V = 20 miles /sec

Explanation:

We have remaining distance   =  d  = 96 miles

Lets call  Pascal velocity  V in miles per hour

Now if he increases his velocity by  50 % (equivalent to multiply by 1.5 ) he will need a time t₁ to arrive then as V = d/t

1.5* V  = d/ t₁      ⇒   1.5 * V  =  96 /t₁

And in the case of reducing his velocity

(V / 4) = d/ (t₁ + 16 )     ⇒  V * (t₁ + 16 ) = 4*d     ⇒ V*t₁ + 16*V = 384

So we a 2 equation system with two uknown variables

1.5*V = 96/t₁      (1)

V*t₁  + 16*V = 384     (2)

We solve  from equation    (1)      t₁  = 64/V

And by substitution   in equation (2)

V * (64/V) + 16* V = 384

64  + 16 *V  = 384         ⇒   16*V = 320      ⇒  V= 320/16

V = 20 miles /sec

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tankabanditka [31]
The velocity at the maximum height will always be 0. Therefore, you will count your final velocity as 0, and your initial velocity as 35 m/s. Next, we know that the acceleration will be 9.8 m/s^2. How? Because the ball is thrown directly upward, and the only force acting on it will be the force of gravity pushing it back down.

The formula we use is h = (Vf^2 - Vi^2) / (2*-9.8m/s^2)

Plugging everything in, we have h = (0-1225)/(19.6) = 62.5 meters is the maximum height.
3 0
3 years ago
Do you think there might be a point in space between Earth and the Moon where the gravity of each would pull on an object equall
Firlakuza [10]

Answer: Yes.

Explanation:

Assuming Earth and Moon are isolated is space, it is possible to have a point where Earth and Moon will pull at an object with equal force.

That point will be closer to the Moon than the Earth because Moon's gravitational field strength is weaker than Earth's gravitational field strength.

7 0
4 years ago
A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with incompressib
victus00 [196]

Answer:

926 N

Explanation:

Metric unit conversion:

R = 18 cm = 0.18 m

r = 5 cm = 0.05 m

The pressure exerted by the F = 12000N car on the wider arm would be ratio of the gravity over area

P = F/A = \frac{F}\pi R^2} = \frac{12000}{2*\pi*0.18^2} = 117892 Pa

The pressure must be the same on the smaller pressure for it to be able to start lifting the car. We can calculate the force f acting on it:

f = Pa = P\pi r^2 = 117892 * \pi * 0.05^2 = 926 N

5 0
3 years ago
An electric motor has an effective resistance of 22 22 and an inductive reactance of 72 12 when working under load. The voltage
Alecsey [184]

Answer:

Current amplitude, I = 5.57 A

Explanation:

It is given that,

Effective resistance, R = 22 ohms

Inductive reactance, L = 72 ohms

Voltage of the alternating source, V = 420 volt

The total impedance of the RL circuit is given by :

Z=\sqrt{R^2+L^2}

Z=\sqrt{(22)^2+(72)^2}

Z = 75.28 ohms

From Ohm's law,

V=I\times Z

I=\dfrac{V}{Z}

I=\dfrac{420}{75.28}

I = 5.57 A

So, the current amplitude of the electric motor is 5.57 A. Hence, this is the required solution.

6 0
4 years ago
Very large accelerations can injure the body, especially if they last for a considerable length of time. One model used to gauge
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Answer:

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How far d does the person travel during the collision if the car was initially moving forward at 4.50 km/h ?

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3 0
3 years ago
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