Question

A fighterjet is launched from an aircraft carrier with the

Answer 1

Answer:

The work done on the jet is $W_{jet} = 2.49\times 10^{7} J$

Given:

Force, F = $2.3\times 10^{5} N$

Distance moved by the jet, x = 87 m

Kinetic Energy, KE = $4.5\times 10^{7} J$

Solution:

Now, to calculate the work done on the fire fighter jet by the catapult, we find the difference between the KE of the jet at lift off and the work done by the engines.

This difference provides the amount of work done on the jet and is given by:

$W_{jet} = KE - W_{engines}$              (1)

Now, the work done by the engines is given by:

$W_{engines} = Fx = 2.3\times 10^{5}\times 87 = 2.001\times 10^{7} J$

Now, using eqn (1):

$W_{jet} = 4.5\times 10^{7} - 2.001\times 10^{7} = 2.49\times 10^{7} J$