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Sever21 [200]
3 years ago
7

When viewing a piece of art that is behind glass, one often is affected by the light that is reflected off the front of the glas

s (called glare), which can make it difficult to see the art clearly. One solution is to coat the outer surface of the glass with a thin film to cancel part of the glare. Part A If the glass has a refractive index of 1.58 and you use TiO2, which has an index of refraction of 2.62, as the coating, what is the minimum film thickness that will cancel light of wavelength 480 nm
Physics
1 answer:
Elza [17]3 years ago
5 0

Answer:

  t = 9.16 10⁻⁸ m

Explanation:

In this exercise we fear a case of interference by reflection,

We have two aspects

* when the light ray passes from the air to the TiO2 that has a higher refraction start, the reflected ray has a phase change of 180º

* when the beam is inside the material its wavelength changes

            λₙ = λ₀ / n

with these two done the equation for destructive interference remains

           2t = m  λₙ

           2nt = m λ₀

They ask us for the thickness t of the film for m = 1

           t = m λ₀ / 2n

let's calculate

          t = \frac{1 \ 480 1 10^9 }{2 \ 2.62}

          t = 9.16 10⁻⁸ m

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6.6 kg block initially at rest is pulled to theright along a horizontal, frictionless surfaceby a constant, horizontal force of
neonofarm [45]

Answer:

v = 3.04 m/s

Explanation:

given,

mass of the block, M = 6.6 Kg

horizontal force, F = 12.2 N

distance, L = 2.5 m

initial speed  = 0 m/s

speed of the block,v = ?

we now

Work done is equal to change in Kinetic energy.

Work done = Force x displacement

W = Δ K E

Δ K E = Force x displacement

\dfrac{1}{2}mv^2 - \dfrac{1}{2}mu^2= F .s

\dfrac{1}{2}\times 6.6 \times v^2 - 0= 12.2\times 2.5

 3.3 v² = 30.5

     v² = 9.242

      v = 3.04 m/s

speed of the block is equal to 3.04 m/s

4 0
3 years ago
Pls help with all questions dew in 10 minutes!
Artyom0805 [142]
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The second largest planet in the solar system

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9. Unlike the other planets of the solar system, Uranus is tilted so far that it essentially orbits the sun on its side, with the axis of its spin nearly pointing at the star.

Uranus' atmosphere is mostly hydrogen and helium, with a small amount of methane and traces of water and ammonia.

As an ice giant, Uranus doesn't have a true surface. The planet is mostly swirling fluids. While a spacecraft would have nowhere to land on Uranus, it wouldn't be able to fly through its atmosphere unscathed either. The extreme pressures and temperatures would destroy a metal spacecraft.

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Neptune has an average temperature of -353 Fahrenheit (-214 Celsius).

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5 0
3 years ago
Which of the following are known to exist on the moon? select all that apply.
denis-greek [22]
B. ice and d basalt............
3 0
3 years ago
Read 2 more answers
If a cup of coffee has temperature 95∘C95∘C in a room where the temperature is 20∘C,20∘C, then, according to Newton's Law of Coo
lina2011 [118]

Answer:

T = 76.39°C

Explanation:

given,

coffee cup temperature = 95°C

Room temperature= 20°C

expression

T( t ) = 20 + 75 e^{\dfrac{-t}{50}}

temperature at t = 0

T( 0 ) = 20 + 75 e^{\dfrac{-0}{50}}

T(0) = 95°C

temperature after half hour of cooling

T( t ) = 20 + 75 e^{\dfrac{-t}{50}}

t = 30 minutes

T( 30 ) = 20 + 75 e^{\dfrac{-30}{50}}

T( 30 ) = 20 + 75 \times 0.5488

T(30) = 61.16° C

average of first half hour will be equal to

T = \dfrac{1}{30-0}\int_0^30(20 + 75 e^{\dfrac{-t}{50}})\ dt

T = \dfrac{1}{30}[(20t - \dfrac{75 e^{\dfrac{-t}{50}}}{\dfrac{1}{50}})]_0^30

T = \dfrac{1}{30}[(20t - 3750e^{\dfrac{-t}{50}}]_0^30

T = \dfrac{1}{30}[(20\times 30 - 3750 e^{\dfrac{-30}{50}} + 3750]

T = \dfrac{1}{30}[600 - 2058.04 + 3750]

T = 76.39°C

4 0
3 years ago
A car with a velocity of 22 m/s is accelerated at a rate of 1.6m/s2 for 6.8s. determine the final velocity
Ivahew [28]

A car with a velocity of 22 m/s is accelerated at a rate of 1.6 m/s^2 for 6.8s has the final velocity t be 32.88 m/s.

The acceleration means the amount of velocity changing per unit time.

The given data:

initial velocity, u = 22 m/s

time, t = 6.8 s

acceleration, a = 1.6 m/s^2

We will be using the equation of motion:

v = u + at

\therefore v=22+1.(6.8)

\Rightarrow v=22+10.88

\Rightarrow v=32.88 \ m/s

The final velocity become 32.88 m/s.

To learn more about Attention here:

https://brainly.in/question/10557838

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3 0
2 years ago
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