1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Minchanka [31]
3 years ago
5

Find the kinetic energy of a bullet weighing 0.10 N if its velocity is 2.0 X 103 m/s?

Physics
1 answer:
irina1246 [14]3 years ago
5 0

The kinetic energy of the bullet is 20.4 kJ.

<u>Explanation:</u>

Kinetic energy of a bullet will be equal to the product of mass of the bullet with the square of velocity or speed of the bullet and then the half of that product value.

But here the mass of the bullet is not given, instead the weight of the bullet is given in terms of force. So from this, we have to first find the mass of the bullet.

We know that as per Newton's second law of motion, force is directly proportional to the product of mass and acceleration. So here the acceleration will be equal to the acceleration due to gravity as it is weight of the object.

So F = mg

0.10 N = m × 9.8

So ,the mass of the bullet is 0.0102 kg.

Now, we know the mass and velocity of the bullet is given as 2000 m/s.

So,

kinetic energy = \frac{1}{2} × m × v²

kinetic energy = 0.5 × 0.0102 × 2000 × 2000 = 20.4 kJ

Thus, the kinetic energy of the bullet is 20.4 kJ.

You might be interested in
Kuiper Belt objects are composed of which substances? Select all that apply.
levacccp [35]
IM sure there is C, D, and E in kuiper belts, but not really sure of silicon and iron

8 0
3 years ago
Which of the following is most useful to determine how much energy is being used by a circuit in a given amount of time?
user100 [1]

Answer:

The answer is A.

Explanation:

5 0
3 years ago
Choose the answer to fill in the blank, which best completes the sentence.
Allisa [31]

Answer:

A on edge 2020

Explanation:

4 0
2 years ago
Read 2 more answers
A 12-kg piece of metal displaces 1.6 L of water when submerged. Part A Find its density. Express your answer to two significant
Tatiana [17]

Answer:

ρ = 7500 kg/m³

Explanation:

Given that

mass ,m = 12 kg

Displace volume ,V= 1.6 L

We know that

1000 m ³ = 1 L

Therefore V= 0.0016 m ³

When metal piece is fully submerged

We know that

mass = Density x volume

m=\rho \times V

Now by putting the values in the above equation

\rho=\dfrac{12}{0.0016}\ kg/m^3

ρ = 7500 kg/m³

Therefore the density of the metal piece will be  7500 kg/m³.

6 0
3 years ago
In which condition the acceleration of a moving vehicle become zero​
Alekssandra [29.7K]

Explanation:

When,the vehicle has uniform velocity, it's acceleration becomes zero

4 0
3 years ago
Other questions:
  • In each case, a charged rod, made of the dense rubber ebonite, comes close or is in contact with the top of an electroscope. The
    11·2 answers
  • When you apply a force to an object what pushing back on you?
    7·1 answer
  • A force is applied to a block sliding along a surface (Figure 2). The magnitude of the force is 15 N, and the horizontal compone
    5·1 answer
  • When referring to body composition we are talking about our leanness. Lean muscle burns _________ calories than fat.
    5·1 answer
  • An MRI technician moves his hand from a region of very low magnetic field strength into an MRI scanner's 2.00 T field with his f
    15·1 answer
  • Some rearview mirrors produce images of cars to your rear that are smaller than they would be if the mirror were flat.Are the mi
    5·1 answer
  • A skier starts from rest at the top of a hill that is inclined 10.5° with respect to the horizontal. The hillside is 200 m long,
    10·1 answer
  • At the equator, the earth spins a distance of
    8·1 answer
  • Which statement is a hypothesis?
    8·2 answers
  • If we interpret the large, angular rocks to have originated from the outcrop at the top of the hill, we are using __________ rea
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!